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3 years ago

6

Elias serves a volleyball at a velocity of 16 m/s. The mass of the volleyball is 0.27 kg. What is the height of the volleyball a

bove the gym floor when its total mechanical energy is 41.70 J? Round to the nearest tenth\

2 answers:

evablogger [386]3 years ago

7 0

Ingenuity says that the answer is 2.7 m

givi [52]3 years ago

4 0

Hello! The anwser is 2.7! I hope this helps! ^^

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A mass m = 550 g is hung from a spring with spring constant k = 2.8 N/m and set into oscillation at time t = 0. A second, identi

riadik2000 [5.3K]

Answer:

The second system must be set in motion $t=0.70s$ seconds later

Explanation:

The oscillation time, T, for a mass, m, attached to spring with Hooke's constant, k, is:

$T=2\pi\sqrt(\frac{m}{k} )$

One oscillation takes T secondes, and that is equivalent to a 2π phase. Then, a difference phase of π/2=2π/4, is equivalent to a time t=T/4.

If the phase difference π/2 of the second system relative to the first oscillator. The second system must be set in motion $t=\frac{\pi}{2}\sqrt(\frac{m}{k})=\frac{\pi}{2}\sqrt(\frac{0.55}{2.8}= 0.70s)$ seconds later

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3 years ago

Which information is necessary to determine an object's speed?

lana [24]

Answer:

1. distance and period of time.

Explanation:

The speed is calculated using the formula $k = \frac{d}{t}$

"k" is the speed, "d" is the distance and "t" is the time.

You need distance and time to calculate the speed.

Speed is how fast an object is going. The direction is irrelevant to speed, not to be confused with velocity, which is speed in a given direction.

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2 years ago

Give reason for the following observation

Irina-Kira [14]

Answer: The smell of hot sizzling food reaches you several metres away, but to get the smell from cold food you have to go close because the kinetic energy of the particles of matter increases with the increase in temperature. In cold foods, kinetic energy is less while in hot foods, kinetic energy is more

hope this helps

3 0

3 years ago

Read 2 more answers

A protester carries his sign of protest, starting from the origin of an xyz coordinate system, with the xy plane horizontal. He

OverLord2011 [107]

Answer:

Part A:

$Displacement\ vector= -40\hat i+20\hat j+25\hat k$

Part B:

Magnitude of displacement=44.721359 m

Explanation:

Given Data:

40 m in negative direction of the x axis

20 m perpendicular path to his left (considering +ve y direction)

25 m up a tower (Considering +ve z direction)

Required:

In unit-vector notation, what is the displacement of the sign from start to end.
The magnitude of the displacement of the sign from start to this new end=?

Solution:

Part A:

$Displacement= (0-40)\hat i+(0+20)\hat j+(0+25)\hat k\\Displacement= -40\hat i+20\hat j+25\hat k$

where:

i,j,k are unit vectors

Part B:

Sign falls to foot of tower so z=0

$Displacement= -40\hat i+20\hat j+0\hat k$

Magnitude of displacement:

$Magnitude\ of\ displacement=\sqrt{(-40)^2+(20)^2+0^2} \\Magnitude\ of\ displacement=44.721359\ m$

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2 years ago

Which of the following methods is the most effective in determining muscular strength if you do not want to worry about selectin

kotegsom [21]

Predicting 1 RM is the most effective method in determining muscular strength if you do not want to worry about selecting the wrong weight. The correct answer is C.

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3 years ago

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