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Paraphin [41]
2 years ago
10

In terms of entropy and energy, systems in nature tend to undergo changes toward

Chemistry
1 answer:
andrew-mc [135]2 years ago
7 0
Number 2 lower entropy and higher entropy
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Name one physical and one chemical property of hydrogen?
Kisachek [45]

Answer:

it is gaseous in nature

it has lower solubility

8 0
3 years ago
What is the definition of a chemical bond?
Makovka662 [10]

A thing used to tie something or to fasten things together.

"she brushed back a curl that had strayed from its bonds"

OR

An agreement with legal force, in particular.

5 0
3 years ago
Read 2 more answers
Gaseous hydrogen iodide is placed in a closed 1.0 L container at 425°C, where it partially decomposes to hydrogen and iodine in
Pie

Answer:

ΔG° = 23192 J/mol

Explanation:

For the reaction:

2 HI (g) ⇌ H₂(g) + I₂(g)

It is possible to find Kp thus:

Kp = P(H₂) P(I₂) / P(HI)²

Replacing:

Kp = 4,79x10⁻⁴ × 4,79x10⁻⁴ / (3,53x10⁻³)²

Kp = 0,0184

<em>As moles of products (2) are the same moles of reactants, Kp = K</em>

It is possible to find ΔG° from K, thus:

ΔG° = -RT ln K

where R is <em>8,314472J/molK</em>, temperature in kelvin is 425 + 273,15 = <em>698,15K </em>and K is <em>0,0184</em>

<em />

Replacing:

ΔG° = -<em>8,314472J/molK </em>× <em>698,15K</em>  ln <em>0,0184</em>

<em>ΔG° = 23192 J/mol</em>

<em />

I hope it helps!

8 0
3 years ago
5. Desde 100 g de un compuesto formado por carbono, hidrogeno y oxígeno, se obtiene 39,132 g de agua y 95,656 g de CO2. Determin
Paha777 [63]

Answer:

      CH_2O_2

Explanation:

The question in English is:

<em>5. From 100 g of a compound formed by carbon, hydrogen and oxygen, 39.132 g of water and 95.656 g of CO₂ are obtained. Determine:</em>

<em />

<em>A. The empirical formula of the compound.</em>

<h2>Solution</h2>

All the carbon of the compound ends as carbon in the CO₂ and all the hydrogen in the compound ends in the water.

<u>1. C in CO₂</u>

Divide the mass of CO₂ by its molar mass and multiply by the molar mass of C:

        96.656g\times \dfrac{12.011g/mol}{44.01g/mol}=26.379gC

<u>2. H in H₂O</u>

Divide the mass of H₂O by its molar mass and multiply by 2 times the molar mass of H:

        39.132g\times \dfrac{(2\times 1.008)g/mol}{18.015g/mol}=4.379gH

<u>3. Calculate O by difference</u>

     100g-26.379g-4.379g=69.242gO

<u>4.Divide the mass of each element by the corresponding atomic mass to find the number of moles of the element</u>

  • C: 26.379g / (12.011g/mol) = 2.196 mol
  • H: 4.379g / (1.008g/mol) = 4.344 mol
  • O: 69.242g / (15.999g/mol) = 4.328 mol

<u />

<u>5. Divide by the least number of moles</u>

  • C: 2.196/2.196 = 1
  • H: 4.344 / 2.196 ≈ 2
  • O: 4.328 / 2.196 ≈ 2

Those are the subscripts of the empirical formula:

<u>6. Empirical formula</u>

         CH_2O_2

7 0
3 years ago
What is the relationship between the strength of the magnetic field and the deflection of the galvanometer needle?
Karo-lina-s [1.5K]

Answer:

Similarly, if magnet is held stationary and the coil is moved away and towards the magnet, the galvanometer shows deflection in similar manner. It is also seen that, the faster the change in the magnetic field, the greater will be the induced emf or voltage in the coil.

please mark me brilliance

3 0
1 year ago
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