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Arte-miy333 [17]
3 years ago
14

The amount of force needed to sustain motion of a rock in outer space is

Physics
1 answer:
BartSMP [9]3 years ago
4 0

Answer:

0 N

Explanation:

According to Newton's first law, object subjected to no force or 0 net force will stay in the same motion. In outer space, there's no gravity or air resistance. So if the net force is 0, a rock in motion would be still in motion forever without a need of an extra force to sustain it.

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Can someone please help me with this !!!!
lukranit [14]

Answer:

I'm not sure but I think it's 4.5 v

3 0
3 years ago
Calculate the specific gravity of a pure gold nugget (ρ = 19.3 g/cm3)
Natasha2012 [34]
We know, For a substance they both are equal in magnitude, i.e., 

Specific Gravity = Density 
Specific Gravity = 19.3      [ As Density = 19.3 ]

In short, option C would be your correct Answer!

Hope this helps!
7 0
3 years ago
Calculate the gravitational force on the washers using the formula F = ma where a = 10 m/s2 and m is the mass of the washers. Us
Radda [10]

0.049

0.098

0.147

0.196

6 0
4 years ago
Read 2 more answers
how does the electric force between two charged particles change if the distance between them is increased by a factor of 3? a.
Anna007 [38]
D. it is decreased by a factor of 9.

Force = kqq ÷ r^2

The distance is squared so if it is increased or decreased by any factor, then it must be squared too. Because the distance is on the bottom of the equation, you divide the force by the increasing or decreasing factor.
6 0
3 years ago
Read 2 more answers
Assuming perfect optics, if the smallest feature you can resolve when observing around 660 nm is of angular size 0.04 arcsec, wh
Dmitriy789 [7]

Answer:

The value is \theta _2 =  0.08 \ arcsec

Explanation:

From the question we are told that

   The first wavelength is  \lambda_1 =  660 \ nm  = 660 *10^{-9 }

   The  first angular size is  \theta_1 =  0.04 \  arcsec

    The second wavelength is  \lambda _2 =  1320 \  nm  =  1320 *10^{-9 } \  m

Generally according to  Rayleigh Criterion we have that

          \theta=  1.22 *  \frac{\lambda }{D}

given every other thing remains constant we have that

         \theta =  k *  \lambda

Here k  represented constant so

         k  =  \frac{\theta }{\lambda}

=>      \frac{\theta_1}{ \lambda_1}  =  \frac{\theta_2}{ \lambda_2}

=>      \frac{\theta_1}{ \theta_2}  =  \frac{\lambda_1}{ \lambda_2}

So

        \frac{ 0.04}{ \theta_2}  =0.5

=>     \theta _2 =  0.08 \ arcsec

3 0
3 years ago
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