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Keith_Richards [23]
4 years ago
5

An object at rest increases its velocity to 10 m/s in 3 seconds. what is its acceleration?

Physics
1 answer:
Anna11 [10]4 years ago
4 0

Answer:

30m

Explanation:

10m per second

there is 3 seconds

10 times 3 is 30

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Which correctly describes electric potential, electric field, and electric (or electrostatic) force?
vlabodo [156]

Answer:

E

Explanation:

A vector is a physical quantity that has magnitude and direction while a scalar is a physical quantity that has magnitude only

*electric potential is a scalar quantity because it only has magnitude

*electric field and electric force are vector quantities because they have magnitude and direction

7 0
3 years ago
An object is moving with an initial velocity of 9m/s. It accelerates at a rate 1.5m/sec2 over a distance of 20m. What is it’s ne
puteri [66]

Answer:

11.87

Explanation:

final velocity^2= initial velocity ^2+ 2* Acceleration* distance

Final Velocity^2= 9*9+2*1.5.20

final velocity^2 = 141

final velocity = 11.87

4 0
4 years ago
Given a wind turbine with blades that sweep out a 10 m diameter circle, and a wind speed of 2 m/s, approximately what is the max
Mars2501 [29]

Answer:

223.55 W

Explanation:

v = Velocity of wind = 10 m/s

r = Radius of circle = 5 m

S = Swept area

\rho = Density of air = 1.2 kg/m³

C_p = Power coefficient = 0.593

P=C_p\frac {1}{2}}\rho Sv^{3}\\\Rightarrow P=0.593\times \frac{1}{2}1.2 \pi \times 5^2\times 2^{3}\\\Rightarrow P=223.55\ W

The maximum possible power that can be produced by the turbine is 223.55 W

8 0
4 years ago
The different odds of survival between a preterm and a full-term newborn involve: cephalic development.
DENIUS [597]

Answer: B

Explanation:

5 0
3 years ago
Doc Brown has calculated his Delorean can accelerate at a rate of 2.52 m/s/s. How
GREYUIT [131]

Answer:

304.89m

Explanation:

Given

acceleration a = 2.52m/s²

final speed v = 39.2m/s

initial speed = 0m/s (car accelerates from rest)

Using the equation of motion below to get the distance of Doc brown from Marty;

v² = u²+2as

substitute the given parameters

39.2² = 0²+2(2.52)s

1536.64 = 0+5.04s

divide both sides by 5.04

1536.64/5.04 = 5.04s/5.04

rearrange the equation

5.04s/5.04 = 1536.64/5.04

s = 304.89m

Hence He and Marty must stand at 304.89m to allow the car to accelerate from rest to a speed  of 39.2 m/s?

6 0
4 years ago
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