Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
Answer:
Step-by-step explanation:
Hello!
Given the probabilities:
P(A₁)= 0.35
P(A₂)= 0.50
P(A₁∩A₂)= 0
P(BIA₁)= 0.20
P(BIA₂)= 0.05
a)
Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)
Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.
b)
Considering that 
you can clear the intersection from the formula 
and apply it for the given events:
c)
The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:
P(B)= (A₁∩B) + P(A₂∩B)= 0.07 + 0.025= 0.095
d)
The Bayes' theorem states that:
Then:
I hope it helps!
Answer:
Sarah is 13 years old
Step-by-step explanation:
Represent Sarah's age with S
Her first brother's age with F
Her second brother's age with B
So, we have:
From the first statement, we have:
---- (1)
From the second, we have:
---- (2)
The product of their ages is 40.
First, we make F the subject in (1) and B the subject in (2)
Their product is represented as follows:
Substitute values for F and B
Open bracket
Subtract 40 from both sides
Factorize:
Split:
or 
But Sarah's age can't be 0 because she has two younger brothers.
So, we stick to
Make S the subject
<em>Hence, Sarah is 13 years old</em>
Option E:
The value of m that makes the inequality true is 5.
Solution:
Given inequality is 3m + 10 < 30.
Let us first simplify the expression.
3m + 10 < 30
Subtract 10 from both side of the equation.
3m < 20 – – – – (1)
<u>To find the value of m that makes the inequality true:</u>
Option A: 20
Substitute m = 20 in (1),
⇒ 3(20) < 20
⇒ 60 < 20
It is not true because 60 is greater than 20.
Option B: 30
Substitute m = 30 in (1),
⇒ 3(30) < 20
⇒ 90 < 20
It is not true because 90 is greater than 20.
Option C: 8
Substitute m = 8 in (1),
⇒ 3(8) < 20
⇒ 24 < 20
It is not true because 24 is greater than 20.
Option D: 10
Substitute m = 10 in (1),
⇒ 3(30) < 20
⇒ 90 < 20
It is not true because 90 is greater than 20.
Option E: 5
Substitute m = 5 in (1),
⇒ 3(5) < 20
⇒ 15 < 20
It is true because 15 is less than 20.
Hence the value of m that makes the inequality true is 5.
Option E is the correct answer.
99 is more than 100 when you add 2 to 99. xD
