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Mekhanik [1.2K]
3 years ago
12

Americans combined drive about 4.0 x 109 kilometers a day and get an average of 20 miles per gallon of gasoline. For each kilogr

am of gasoline that is burned about 3 kg of carbon dioxide (CO2) are produced. With the density of gasoline as 0.93 g/cm3, how many kg of CO2 are emitted by U.S. cars into the atmosphere each minute? (1 gallon = 3.7854 L, 1 mile = 1.609 km)
A. 9.12 x 105 kg CO2/min
B. 5.47 x 107 kg CO2/min
C. 4.7 x 109 kg CO2/min
D. 4.38 x 106 kg CO2/min
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer:

303,882.84649 kg\times 3=9.12\times 10^5 kg of carbon dioxide gas.

Explanation:

Average distance covered by Americans in a day= 4.0\times 10^9 km

1 day = 24 × 60 min = 1,440 min

Average distance covered by Americans in a minute= \frac{4.0\times 10^9 km}{1,440}=2,777,777.78 km

Average mileage of the car = 20 miles/gal = 32.18 km/gal

1 mile = 1.609 km

20 miles = 20 × 1.609 km = 32.18 km

Volume of gasoline used in minute = \frac{2,777,777.78 km}{32.18 km/gal}

V=86,320.00 gal

V=86,320.00\times 3.7854 L

(1 L = 1000 mL)

V=86,320.00\times 3.7854 \times 1000 mL=326,755,748.91 mL

Mass of 86,320.00 gallons of gasoline = m

Density of the gasoline = d = 0.93 g/cm^3=0.93 g/mL

1 mL= 1 cm^3

m=d\times V=0.93 g/mL\times 326,755,748.91 mL

m=303,882,846.49 g=303,882.84649 kg

1 kilogram of gasoline gives 3 kg of carbon dioxde gas .

Then 303,882.84649 kg of gasoline will give :

303,882.84649 kg\times 3=9.12\times 10^5 kg of carbon dioxide gas.

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