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Alexandra [31]
3 years ago
10

Which element is very toxic and reactive green gas?

Chemistry
2 answers:
noname [10]3 years ago
7 0
The answer is Chlorine.
yawa3891 [41]3 years ago
3 0
I would answer this but i have to go to bed i have a reading test tommorow
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1. A student determines the density of water to be 0.966g/ml at a
lions [1.4K]

<u>Answer:</u>

<em>The percentage error in the measurement is 2.4% </em>

<u>Explanation:</u>

The measurement made by the student is 0.966 g/cm^3.

But the actual value of density is 0.943 g/cm^3

The formula to calculate percentage error is  

percentage error = \frac{(measured \ value-actual \ value)}{(actual  \ value)} \times 100

Hence percentage error in this case is given by

<em>Percentage error = \frac{(0.966-0.943)}{0.943} \times 100 </em>

<em>= \frac{0.023}{0.943} \times 100=2.4% </em>

A physical quantities value will be determines by various quantities. If errors are made in measuring any of these quantities there will be error in the measurement of the final physical quantity as well.

Here density of a substance is a derived quantity determined by measuring mass and volume of  that substance.<em> If errors are made in mass and volume measurements the density value will also be erroneous. </em>

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3 years ago
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6 0
3 years ago
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What is the density of a marble that has a mass of 3.023 g and displaces 2.5 mL of water?
Svetradugi [14.3K]
Density= 1.2092 because density = mass/volume
4 0
3 years ago
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On heating 5.03 g of hydrated barium chloride (BaCl2 XH2O), 4.23 g is left behind. What is the name of this hydrate? (
RSB [31]

<span>1)    </span><span>Deduce the two masses and see the amount of water was driven off when heated: </span><span>

<span>5.03 g - 4.23 g = 0.8 g H2O given off </span>

<span>2) Change mass from grams to moles of H2O: </span>

<span>0.8 g H2O / 18 g H2O in 1 mole = 0.044 mol H2O </span>

<span>3) Change left over mass to moles  of BaCl2 .</span></span>

<span>
<span>4.23 g BaCl2 / 207 g BaCl2 in 1 mol = 0.021 mol BaCl2 </span>

<span>4)Find the ratio of mol H2O to mol BaCl2: </span>

<span>0.044 mol H2O : 0.021 mol BaCl2 </span>

<span>5) The resulting  ratio is  2:1 so two H2O for each BaCl2, thus,  the hydrate was named: </span>
<span>Barium chloride di-hydrate</span></span>

8 0
3 years ago
How much heat is released during the process described?
Montano1993 [528]

Answer: no clue

Explanation:

4 0
3 years ago
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