AsH3 has five valence electrons, so the molecule will have 3 bonding domains and one non-bonding domain (lone pair) around the central atom. The geometry is trigonal pyramidal, and the angles are around 107 degrees.
AsH3 and hydrogen are very close in electrongativity, so there really is no partial charges. There may be a slight electron pull towards hydrogen, but it would be nearly insignificant
Answer:
C ) 1.70 g/L
Explanation:
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Also,
Moles = mass (m) / Molar mass (M)
Density (d) = Mass (m) / Volume (V)
So, the ideal gas equation can be written as:
PM=dRt
At STP,
Pressure = 1 atm
Temperature = 273.15 K
Molar mass of fluorine gas = 38 g/mol
Applying the equation as:
1 atm × 38 g/mol = d × 0.0821 L.atm/K.mol × 273.15 K
<u>⇒d = 1.70 g/L</u>
PV=nRT
Here
P1/T1= P2 / T2
1 torr=133 pascal
600 *133 /215 = 750 *133 / t2
T2= 268.75 K
