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3 years ago

How do I make 105 over 8 a mixed number

Mathematics

1 answer:

kaheart [24]3 years ago

8 0

You just divide 105/8 in your calculator, which is 13.125. Since .125=1/8, 13.125 would be 13 1/8.

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In a volleyball game, Caroline served the ball over the net 16 out of 20 times. What percent did she not make her serve over the

brilliants [131]

16/20. We reduce that and get 4/5.

After this it's much simpler to chage it.

100 dividied by 5 is 20. (20,40,60,80,100)

So the 4th number (4/100)

is 80. 80%.

20% she didn't and 80% she did :) (100-80)

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3 years ago

Read 2 more answers

ASAP BRAINLIEST !! Luis is given the fraction 4/5. He is told to create an equivalent fraction with a numerator of 32. Explain t

solniwko [45]

Answer: answer 40.

Step-by-step explanation:

Note : lets make x the missing denominator.

I would take the 4/5 and set it equals to 32/x

we then cross multiply

where it would be 4 * x = 32 * 5

it would then be 4x = 160

we would then divide 160 by 4

x = 160/ 4

and x would be 40

.... therefore the missing denominator is 40.

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3 years ago

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The price Jimmy paid for a video game is. 85x. What was the discount ?

rewona [7]

The discount was 85% off.

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3 years ago

If a^n=b than a is the n^th root of b. True or false

dem82 [27]

Step-by-step explanation:

yes that's true

if a^n=b

then

a^n/n=b^1/n

a=b^1/n

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3 years ago

Assume the general population gets an average of 7 hours of sleep per night. You randomly select 45 college students and survey

tekilochka [14]

Answer:

a) ii. This is a left-tailed test.

b) -1.59

c) -1.301

d) i. reject null hypothesis

e) Option i) The data supports the claim that college students get less sleep than the general population.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 7 hours

Sample mean, $\bar{x}$ = 6.87 hours

Sample size, n = 45

Alpha, α = 0.10

Sample standard deviation, s = 0.55 hours

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 7\text{ hours}\\H_A: \mu < 7\text{ hours}$

a) We use one-tailed(left) t test to perform this hypothesis.

b) Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{6.87 - 7}{\frac{0.55}{\sqrt{45}} } =-1.59$

c) Now,

$t_{critical} \text{ at 0.10 level of significance, 44 degree of freedom } = -1.301$

Since,

$t_{stat} < t_{critical}$

d) We fail to accept the null hypothesis and reject it.

We accept the alternate hypothesis and conclude that mean number of hours of sleep for all college students is less than 7 hours.

e) Option i) The data supports the claim that college students get less sleep than the general population.

8 0

3 years ago