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d1i1m1o1n [39]
3 years ago
14

How is energy transferred between two objects at different temperatures?

Physics
1 answer:
mojhsa [17]3 years ago
4 0

When calculated energy transferred between objects use the definition of heat as

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How do I use a metric conversions chart
Rzqust [24]
Metric Conversion<span> calculators, </span>tables<span> and formulas for temperature, length, area, volume and weight ... </span>Use<span> the search box to find your required </span>metric converter<span>.</span>
4 0
4 years ago
When blue light of wavelength 470 falls on a single slit, the first dark bands on either side of center are separated by 45.0. d
enyata [817]
For Fraunhofer diffraction at a single slit would be represented by: 

<span>a sinθ = mλ 

</span><span>It should be noted that the angle needs be halved because we are only concerned with the angle between m=1 and m=0 and they gave you the angle between m=1 to the right of the center and m=1 on the left of the center. We calculate as follows:
</span>
<span>a sin(45/2)=(1)(470)
a = 1228 nm 

Hope this answers the question. Have a nice day.
</span>
3 0
4 years ago
Part A
Makovka662 [10]

Answer:

(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

Explanation:

Given that,

Mass of marble = 0.0073 kg

Speed = 0.65 m/s

(A). We need to calculate the magnitude of the momentum of the marble

Using formula of momentum

p = mv

Where, m = mass

v = velocity

Put the value into the formula

p=0.0073\times0.65

p=0.004745\ kg m/s

(B). Mass of baseball = 0.136 kg

Momentum of baseball = 3.14 kg m/s

We need to calculate the speed of baseball

Using formula of momentum

p=mv

v=\dfrac{p}{m}

Put the value into the formula

v=\dfrac{3.14}{0.136}

v=23.0\ m/s

Hence, (A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

7 0
3 years ago
A particle initially located at the origin has an acceleration of = 2.00ĵ m/s2 and an initial velocity of i = 8.00î m/s. Find (a
sergejj [24]

a. The particle has position vector

\vec r(t)=\left(\left(8.00\dfrac{\rm m}{\rm s}\right)t\right)\,\vec\imath+\left(\dfrac12\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)t^2\right)\,\vec\jmath

\vec r(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)t\,\vec\imath+\left(1.00\dfrac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath

b. Its velocity vector is equal to the derivative of its position vector:

\vec v(t)=\vec r'(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\vec\imath+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath

c. At t=7.00\,\mathrm s, the particle has position

\vec r(7.00\,\mathrm s)=\left(8.00\dfrac{\rm m}{\rm s}\right)(7.00\,\mathrm s)\,\vec\imath+\left(1.00\dfrac{\rm m}{\mathrm s^2}\right)(7.00\,\mathrm s)^2\,\vec\jmath

\vec r(7.00\,\mathrm s)=\left(56.0\,\vec\imath+49.0\,\vec\jmath\right)\,\mathrm m

That is, it's 56.0 m to the right and 49.0 m up relative to the origin, a total distance of \|\vec r(7.00\,\mathrm s)\|=\sqrt{(56.0\,\mathrm m)^2+(49.0\,\mathrm m)^2}=74.4\,\mathrm m away from the origin in a direction of \theta=\tan^{-1}\dfrac{49.0\,\mathrm m}{56.0\,\mathrm m}=41.2^\circ relative to the positive x axis.

d. The speed of the particle at t=7.00\,\mathrm s is the magnitude of the velocity at this time:

\vec v(7.00\,\mathrm s)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\vec\imath+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)(7.00\,\mathrm s)\,\vec\jmath

\vec v(7.00\,\mathrm s)=\left(8.00\,\vec\imath+14.0\,\vec\jmath\right)\dfrac{\rm m}{\rm s}

Then its speed at this time is

\|\vec v(7.00\,\mathrm s)\|=\sqrt{\left(8.00\dfrac{\rm m}{\rm s}\right)^2+(14.0\dfrac{\rm m}{\rm s}\right)^2}=16.1\dfrac{\rm m}{\rm s}

4 0
3 years ago
If Home Depot, Delta Faucets, and Armstrong Floor Coverings pay for a television show about remodeling a kitchen on the Home and
Lyrx [107]

Answer:

The options for this question are:

A) buying time spots for

B) purchasing network time for

C) creating infomercials for

D) sponsoring

E) advertising

The correct answer is D) sponsoring .

Explanation:

Sponsorship is an advertising strategy that consists of an organization (sponsor) committing to provide financing to a third party (sponsored) in exchange for the presentation of its brand or product.

The sponsorship consists of an agreement or agreement between two people (legal or physical) in which, one of the parties called sponsor, will deliver a consideration (monetary or material) to another sponsored call, so that the latter exposes its brand or product publicly.

Sponsorship Objective

Sponsorship is a subtle form of advertising where the company seeks that customers associate their brand with an activity or person that represents values ​​or qualities that attract their customers. These activities or people are usually outside the scope of the normal activity of the company, for example: a prestigious event, an admired athlete or the celebration of a relevant event, etc.

The ultimate goal of sponsorship is to attract customers and increase sales.

7 0
3 years ago
Read 2 more answers
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