How is energy transferred between two objects at different temperatures?
1 answer:
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Answer:
The order of increasing energy is as follows
"microwave < infrared < visible < ultraviolet"
Option (A) is correct.
Explanation:
Given:
Arrange the following spectral regions in order of increasing energy: infrared, microwave, ultraviolet, visible.
From the formula of energy in terms of frequency.
Where planck constant,
frequency of light.
From above formula we can conclude that higher frequency means higher energy.
In our case ultraviolet has higher frequency and microwave has lower frequency.
So ultraviolet has higher energy and microwave has lower energy.
microwave < infrared < visible < ultraviolet
Therefore, the order of increasing energy is as follows
"microwave < infrared < visible < ultraviolet"
A) -2.0 m
Look at the ray diagram attached in the picture, where:
p identifies the location of the object
q identifies the location of the image
F identifies the focus of the mirror
Each tick represents 1 m
We have
p = 6.0 m is the distance of the object from the mirror
f = -3.0 m is the focal length
From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so
q = -2.0 m
This can also be verified by using the mirror equation:
B) Upright and virtual
As we see from the picture, the image is upright, since it has same orientation as the object.
Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,
- An image is said to be real if it is on the same side of the object
- An image is said to be virtual if it is on the opposite side of the mirror
Therefore, this means that the image is virtual.
Answer:
(a) 0.345 T
(b) 0.389 T
Solution:
As per the question:
Hall emf,
Magnetic Field, B = 0.10 T
Hall emf,
Now,
Drift velocity,
Now, the expression for the electric field is given by:
(1)
And
Thus eqn (1) becomes
where
d = distance
(2)
(a) When
(b) When