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Crazy boy [7]
3 years ago
15

Is the following nuclear equation balanced? The pic is down below

Physics
2 answers:
pantera1 [17]3 years ago
5 0

i agree with milkyway it is balanced.

vagabundo [1.1K]3 years ago
4 0
Yes the equation is balanced
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A trumpet player, using her ear, hears 5 beats per second when she plays a note on her trumpet and simultaneously sounds a 440 H
german

<h2>Frequency of trumpet wire = 445 Hz</h2>

Explanation:

The given  frequency of tuning fork is 440 Hz . It produces 5 beats with trumpet wire . That means , the frequency of wire can be 440 ± 5

It can be either 445 or 435

Now the length of wire is increased , by which its frequency decreases . Because frequency is inversely proportional to length of wire .

If we decrease the frequency in 435 , the difference between tuning fork frequency and wire frequency will become greater than 5 even . So it cannot produce 3 beats with it .

If we decrease frequency from 445 , it can become 443 Hz . It gives 3 beat with the tuning fork as given .

Thus the initial frequency of wire is 445 Hz

4 0
3 years ago
A ship's anchor weighs 5000N. It's cable passes over a roller of negligible mass and is wound around a hollow cylindrical drum o
deff fn [24]
Hi! Great first step would be to understand the scenario (in my opinion). So two great ways would be to draw a picture or rephrase it. If something else works, do that! You just need to "see" the situation so that you can take some away from it.

Then I think a good next step is to conceptualize everything. Put everything into a context like a physics book would. The anchor is pulled 5000N downward - that's weight. The roller will act like a pulley, and we can ignore it's properties except that it's part of a pulley system (we can ignore stuff because it has "negligible" mass and no other details are given). And then we have the hollow cylindrical drum with one radius measurement given; so we can think of this as a made-up shape with mass - a cylindrical soda can without a top or bottom (but no thickness) and a 380kg mass. The anchor is drops 16m. It hints at energy. The energy that the drum gets is all do to this anchor pulling on the rope (which is really just a means of transferring force, since we neglect its mass and get no details).

Feel free to pause here to make sure you can get the scenario in your head.

So, we want to know something about the barrel as it's rolling. The rotation rate. How many turns per some time. But don't worry yet, we can find a way to work that in. Since the rope pulls and spins the drum, the drum is spun, and gets energy. One way to find the kinetic energy of the spinning drum uses the radius, mass, and rate of rotation. More on that soon.

And how does having some equation with the drum's kinetic energy, radius, mass, and rate of rotation help? Well, we can find all of those except our rate of rotation and solve for the rate of rotation. The energy is the only mystery, but that all comes from the dropping anchor. Can we find that energy? Yeah, there's a way to find the energy that gravity gives our anchor based on it's the force and how far that force moves it.

So, first for the anchor. Linear work is simple:  W=F d
So you have your force and distance we associate with the anchor, so you have your work. We'll call that "W_1" when we need it.

Next the drum's situation. Thanks to http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html, we have the equation for kinetic energy.
Generally, we have <em></em>KE=\frac12I\omega^2, and we need the "I," which deals with rotational inertia. That is pretty much how hard it is to rotate the drum based only on the idea that your getting the mass to move (acceleration). That site refers to our hollow drum as a "hoop," and gives says that we can consider the rotational inertia to be I=MR^2. Now that we know the rotational inertia, we can use good old mathematical substitution to get the kinetic energy to look like
KE=\frac12MR^2\omega^2
And we can rearrange that to get
\omega=\sqrt{\frac{2KE}{MR^2}}=\sqrt{\frac{2KE}{M}}\cdot\frac1R

Since the energy change from the anchor's fall is the energy change of the drum, this KE is the "W_1" from before. So
\omega=\sqrt{\frac{2W_1}{M}}\cdot\frac1R=\sqrt{\frac{2\left(F d\right)}{M}}\cdot\frac1R

Now everything's set up. It's a matter of checking my work, carefully using a calculator, and making sure the answer makes sense (ie. this should be a lot of energy - much more than 1 Joule). Also, follow up by making sure you can do it again, alone. And feel free to ask or lookup questions you need along the way if there are missing pieces in your understanding.

Good luck! :)
5 0
3 years ago
Four students were loading boxes of food collected during a food drive. The force that each student exerted while lifting and th
Fudgin [204]

Answer:

it is B

Explanation:

Edge2020

7 0
3 years ago
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good morning to you all! someone please answer this, ill give you brainliest and you will earn 50 points.
Shalnov [3]

Natural hazards do not have to be natural disasters. What are some of the ways modern technology can help prevent future natural disasters?

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<u> </u><u> </u><u> </u><u> </u><u> </u><u>Seismographs</u><u> </u><u>are</u><u> </u><u>the</u><u> </u><u>devices</u><u> </u><u>that</u><u> </u><u>respond</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>ground</u><u> </u><u>shaking</u><u> </u><u>before</u><u> </u><u>volcanic</u><u> </u><u>eruption</u><u>,</u><u> </u><u>earthquake</u><u> </u><u>and</u><u> </u><u>explosions</u><u>.</u>

3 0
2 years ago
Read 2 more answers
What term represents the total length of a path taken by an object?
denpristay [2]

Hey there!

I would say either B or C

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx

3 0
3 years ago
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