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matrenka [14]
3 years ago
6

the diagram below represents the orbits of earth, comet temple-tuttle, and planet x, another planet in out solar system. arrows

on each orbit represent the direction of movement. which objects orbit would have and eccentricity close to 1?

Physics
1 answer:
mart [117]3 years ago
5 0

Answer:

the most elliptical orbit is that of COMETA

Explanation:

The eccentricity of a curve in defined as the ratio between lacia to the focus, called c and the value of the axis greater than

         ε = c / a

if we use Pythagoras' theorem

         c = \sqrt{a^2 - b^2}

   substituting

           ε = \sqrt{1 - (b/a)^2 }

if   ε = 0 we have a circumference

In the diagram presented the orbit of the comet is an ellipse a> b

          ε=\sqrt{1- x}  \\ x = (\frac{b}{a} )^2

if we expand in series

             ε = 1 - x/2  

             ε=  1 - \frac{1}{2}  \ (\frac{ b}{a} )^2

if we neglect the non-linear terms

            ε = 1

Earth's orbit is a small ellipse

             b / a = 149 10⁶ / 151 10⁶

             b / a = 0.98675

             ε = \sqrt{1- 0.98675^2}

               ε = 0.16

a very small ellipse

Planet X, despite not having data, it seems that the sun is in the scepter of the orbit, so b = a

therefore  both the semi-axes of the curve

        e = a / b

Consequently, the most elliptical orbit is that of COMETA.

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7 0
3 years ago
A 3.00-kg object has a velocity 16.00 i ^ 2 2.00 j ^2 m/s.
trapecia [35]

Answer:

390 J

Explanation:

m = 3 kg

u = 16 i + 2 j

(a) Magnitude of velocity = \sqrt{16^{2}+2^{2}} = 16.1245 m/s

KEi = 1/2 m v^2 = 0.5 x 3 x 16.1245 = 390 J

(b) v = 18 i + 14 j

Magnitude of velocity =  \sqrt{18^{2}+14^{2}} = 22.804 m/s

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According to the work energy theorem

Work done = change in KE = KEf - KEi = 780 - 390 = 390 J

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4 years ago
A skateboarder rolls horizontally off the top of a staircase and lands at the bottom. The staircase has a horizontal length of 1
TiliK225 [7]

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3 0
3 years ago
True or False.The magnetic fields of both Uranus and Neptune are highly tilted relative to their rotation axes and significantly
MA_775_DIABLO [31]

Answer:

True.

Explanation:

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8 0
3 years ago
Please answerASAP
Illusion [34]

Answer:

8.9 m/s^2

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the lenght of the pendulum

g is the acceleration due to gravity at the location of the pendulum

We notice from the formula that the period of a pendulum does not depend on the mass of the system

In this problem:

-The pendulum comes back to the point of release exactly 2.4 seconds after the release. --> this means that the period of the pendulum is

T = 2.4 s

- The length of the pendulum is

L = 1.3 m

Re-arranging the equation for g, we can find the acceleration due to gravity on the planet:

g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{2.4})^2(1.3)=8.9 m/s^2

7 0
4 years ago
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