Answer:
a. ![\alpha =2122.22\: rev/s^{2}](https://tex.z-dn.net/?f=%5Calpha%20%3D2122.22%5C%3A%20rev%2Fs%5E%7B2%7D)
b. ![\Delta \theta =9,550.02\: rev](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%20%3D9%2C550.02%5C%3A%20rev)
Explanation:
The computation is shown below:
data provided in the question
The initial angular velocity
= 0 rev/s,
f = Final angular velocity =
= 382000 rpm i.e =
= 6,366.67
And time = t = 3.0s
Based on the above information
a. For angular acceleration of drill
![\small \omega =\omega _{o}+\alpha t \\\\\ 6,366.67 = 0 + \alpha (3.0) \\\\ \alpha =2122.22\: rev/s^{2}](https://tex.z-dn.net/?f=%5Csmall%20%5Comega%20%3D%5Comega%20_%7Bo%7D%2B%5Calpha%20t%20%5C%5C%5C%5C%5C%206%2C366.67%20%3D%200%20%2B%20%5Calpha%20%283.0%29%20%5C%5C%5C%5C%20%5Calpha%20%3D2122.22%5C%3A%20rev%2Fs%5E%7B2%7D)
b. For the number of revolutions
![\small \omega ^{2}-\omega _{o}^{2}=2\alpha \Delta \theta \\\\(6,366.67) ^{2}-(0)^{2}=2(2122.22) \Delta \theta \\\\ \Delta \theta =9,550.02\: rev](https://tex.z-dn.net/?f=%5Csmall%20%5Comega%20%5E%7B2%7D-%5Comega%20_%7Bo%7D%5E%7B2%7D%3D2%5Calpha%20%5CDelta%20%5Ctheta%20%5C%5C%5C%5C%286%2C366.67%29%20%5E%7B2%7D-%280%29%5E%7B2%7D%3D2%282122.22%29%20%5CDelta%20%5Ctheta%20%5C%5C%5C%5C%20%5CDelta%20%5Ctheta%20%3D9%2C550.02%5C%3A%20rev)
We simply applied the above formulas for determining each parts
The correct answer is a direct current
Answer:
diffracted into semicircular waves. constructive interference occurs where the waves are crest to crest or trough to trough, destructive interference occurs where they are crest to trough. The light that falls on the screen produces bands of light and dark fringes on the screen as a result of these constructive and destructive interferences. This is called the young's slit experiment.
Answer: ![0.985\times 10^{-4}\ T](https://tex.z-dn.net/?f=0.985%5Ctimes%2010%5E%7B-4%7D%5C%20T)
Explanation:
Given
Electron is accelerated 3.5 kV potential difference
Distance between plates d=29 mm
The potential difference between plates is V=100 V
here, the kinetic energy of an electron is acquired through a potential difference of 3.5 kV
![\Rightarrow \dfrac{1}{2}m_ev^2=e\times 3.5\times 10^3\\\\\Rightarrow v=\sqrt{\dfrac{2\times 3.5\times 10^3e}{m_e}}=\sqrt{\dfrac{7\times 10^3\times 1.6\times 10^{-19}}{9.1\times 10^{-31}}}\\\\\Rightarrow v=\sqrt{1.23\times 10^{15}}=3.5\times 10^7\ m/s](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B1%7D%7B2%7Dm_ev%5E2%3De%5Ctimes%203.5%5Ctimes%2010%5E3%5C%5C%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%203.5%5Ctimes%2010%5E3e%7D%7Bm_e%7D%7D%3D%5Csqrt%7B%5Cdfrac%7B7%5Ctimes%2010%5E3%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%7D%7D%5C%5C%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B1.23%5Ctimes%2010%5E%7B15%7D%7D%3D3.5%5Ctimes%2010%5E7%5C%20m%2Fs)
To move in a straight line Force due to magnetic field must be balanced by force due to charge
![\Rightarrow F_B=F_q\\\\\Rightarrow evB=eE\\\\\Rightarrow B=\dfrac{E}{v}\\\\\Rightarrow B=\dfrac{\frac{V}{d}}{3.5\times 10^7}=\dfrac{\frac{100}{0.029}}{3.5\times 10^7}\\\\\Rightarrow B=\dfrac{3.448\times 10^3}{3.5\times 10^7}=0.985\times 10^{-4}\ T](https://tex.z-dn.net/?f=%5CRightarrow%20F_B%3DF_q%5C%5C%5C%5C%5CRightarrow%20evB%3DeE%5C%5C%5C%5C%5CRightarrow%20B%3D%5Cdfrac%7BE%7D%7Bv%7D%5C%5C%5C%5C%5CRightarrow%20B%3D%5Cdfrac%7B%5Cfrac%7BV%7D%7Bd%7D%7D%7B3.5%5Ctimes%2010%5E7%7D%3D%5Cdfrac%7B%5Cfrac%7B100%7D%7B0.029%7D%7D%7B3.5%5Ctimes%2010%5E7%7D%5C%5C%5C%5C%5CRightarrow%20B%3D%5Cdfrac%7B3.448%5Ctimes%2010%5E3%7D%7B3.5%5Ctimes%2010%5E7%7D%3D0.985%5Ctimes%2010%5E%7B-4%7D%5C%20T)
The best answer is B. Atoms absorb different wavelengths of light based on stuff with electrons that I can't remember too well. Just know that it is wavelengths.