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3 years ago

Pwease hlp me (>O<) Darkness falls during daytime hours. Which event might have occurred?

Physics

2 answers:

Tcecarenko [31]3 years ago

7 0

Answer:

D. Solar Eclipse

Explanation:

This is quite a phenomenal occurrence. Please, allow me to explain why D is correct.

A. A New Moon: This is the moon's first lunar phase. This is such a phase during which the sun and earth are located at nearly precise opposite ends of the moon, an occurrence that renders the moon nearly (if not) entirely invisible by the naked eye from an earthly perspective. This is not an occurrence that renders darkness during daylight.

B & C: (Partial & Total) Lunar Eclipse: A Lunar Eclipse is a beautiful occurrence that is visible only during nightfall, but can be witnessed from any location on earth that is currently facing away from the sun (a.k.a. nighttime hours). This occurs when the earth, sun, and moon are nearly perfectly aligned, with the sun and moon at opposite ends of the earth. The earth blocks the light of the sun, and though the side facing the sun won't experience any difference, the side facing away from the sun will be able to see the light from the sun beam around the earth, hitting the moon and reflecting back on us. The shadow of the earth entirely covers the moon during this event. The phases determines exactly what we see and to what degree/extent. This eclipse itself can happen numerous times a year, though only in Partial or Penumbral phases.

D. A Solar Eclipse: A solar eclipse is a breathtaking and oftentimes somewhat terrifying occurrence during which the moon passes perfectly in between the earth and the sun. Unlike a New Moon, however, this occurrence is perceived during the day, so for the side of the earth FACING the sun. When the moon is making its journey in between the sun and earth (which takes roughly 3-5m), the massive silhouette of the moon can be seen blotting out the sun, effectively causing a brief moment of darkness during daytime hours. This occurence is considered remarkably rare because DESPITE it occuring once per year, it can ONLY be viewed from specific locations on earth.

slamgirl [31]3 years ago

5 0

Answer:

D, solar eclipse, it can only be dark in daylight hours with totality and you only get that with a total solar eclipse

Explanation:

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A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

aalyn [17]

Answer:

4.56 s

Explanation:

Let t (seconds) be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. Since prior to this they are traveling at constant speed, they would have maintained a distance of 52 m before accelerating.

The distance traveled by the car, with respect the motorcycle position when it start accelerating is

$s_c = s_0 + v_ct = 52 + 19t$

The distance traveled by the motorcycle after accelerating, with respect the motorcycle position when it start accelerating is

$s_m = v_mt + at^2/2 = 19t + 5t^2/2$

When the motorcycle catches up to the car, their position are at the same

$s_c = s_m$

$52 + 19t = 19t + 5t^2/2$

$52 = 5t^2/2$

$t^2 = 20.8$

$t = \sqrt{20.8} = 4.56 s$

5 0

3 years ago

Please Help. I would Really Appreciate it

Readme [11.4K]

Answer:

a) 0.60 kg cart has final velocity 3.0 m/s [E]

0.80 kg cart has final velocity 4.0 m/s [W]

b) 0.12 m

Explanation:

Take east to be positive.

a) Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.60) (-5.0) + (0.80) (2.0) = (0.60) v₁ + (0.80) v₂

-1.4 = 0.6 v₁ + 0.8 v₂

Kinetic energy is conserved in elastic collisions.

½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²

m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²

(0.60) (-5.0)² + (0.80) (2.0)² = (0.60) v₁² + (0.80) v₂²

18.2 = 0.6 v₁² + 0.8 v₂²

Solve the system of equations.

-1.4 = 0.6 v₁ + 0.8 v₂

-1.4 − 0.6 v₁ = 0.8 v₂

-1.75 − 0.75 v₁ = v₂

18.2 = 0.6 v₁² + 0.8 (-1.75 − 0.75 v₁)²

18.2 = 0.6 v₁² + 0.8 (3.0625 +2.625 v₁ + 0.5625 v₁²)

182 = 6 v₁² + 8 (3.0625 + 2.625 v₁ + 0.5625 v₁²)

182 = 6 v₁² + 24.5 + 21 v₁ + 4.5 v₁²

0 = 10.5 v₁² + 21 v₁ − 157.5

0 = v₁² + 2 v₁ − 15

0 = (v₁ − 3) (v₁ + 5)

v₁ = 3 or -5

Since u₁ = -5.0 m/s, v₁ must be 3.0 m/s.

Solving for v₂:

v₂ = -0.75 v₁ − 1.75

v₂ = -4.0 m/s

b) The compression of the spring is a maximum when the carts have the same velocity.

Momentum is conserved.

m₁u₁ + m₂u₂ = (m₁ + m₂) v

(0.60) (-5.0) + (0.80) (2.0) = (0.60 + 0.80) v

-1.4 = 1.4 v

v = -1.0

Energy is conserved.

½ m₁u₁² + ½ m₂u₂² = ½ (m₁ + m₂) v² + ½ kx²

m₁u₁² + m₂u₂² = (m₁ + m₂) v² + kx²

(0.60) (-5.0)² + (0.80) (2.0)² = (0.60 + 0.80) (-1.0)² + (1200) x²

18.2 = 1.4 + 1200 x²

16.8 = 1200 x²

x² = 0.014

x = 0.12

5 0

4 years ago

Where is the deepest part of the ocean

Mariana [72]

Answer:

Trenches are the deepest part of the oceans, narrow and long depressions on the sea floor. One good example is the Mariana Trench, the deepest part of the ocean

Explanation:

5 0

3 years ago

What is a difference between newton’s laws of motion and einstein’s theory of relativity?newton’s laws are factual statements, w

Tom [10]

Einstein’s theory can found E = mc 2
Issac Newton was found universal gravitional (gravity) opinion.newton’s laws can be revised over time, but einstein’s theory of relativity

5 0

3 years ago

A fugitive tries to hop on a freight train traveling at a constant speed of 5.5 m/s. Just as an empty box car passes him, the fu

stiks02 [169]

Th equations to be used here are the following:

a = (v - v₀)/t
x = v₀t + 0.5at²

The speed of the fugitive is the sum of his own speed plus the speed of the train. Thus,
v₀ = 0 + 5.5 m/s = 5.5 m/s
v = 8 m/s + 5.5 m/s = 13.5 m/s

a.) We use the first equation to determine time
2.5 m/s² = (13.5 m/s - 5.5 m/s)t
Solving for t,
t = 3.2 seconds

b.) We use the answer in a) and the 2nd equation:

x = (5.5 m/s)(3.2 s) + 0.5(2.5 m/s²)(3.2 s)²
x = 30.4 meters

3 0

3 years ago