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Vlad [161]
3 years ago
10

What is the final velocity of a rocket that is traveling at 205 m/s and accelerates at

Physics
1 answer:
-Dominant- [34]3 years ago
7 0

Answer:

70,100 m/s

Explanation:

Given:

v₀ = 205 m/s

a = 8.03 m/s²

Δx = 1750 m

Find: v

v² = v₀² + 2aΔx

v² = (205 m/s)² + 2 (8.03 m/s²) (1750 m)

v = 70,130 m/s

Rounding to three significant figures, the final velocity is 70,100 m/s.

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2<br><br> How does Descartes' "quality of motion" differ from the modern<br><br> momentum?
Rzqust [24]

Answer: Descartes was more of speed which defers from modern day velocity.

Explanation:

Descartes law if conservation referred or defined “motion” rather than “momentum” as what is obtainable in today's world as ”speed” the rate at which something moves rather than “velocity” which is a product of speed and direction. So in conclusion Descartes was more of speed which defers from modern day velocity.

6 0
3 years ago
Two 125 kg bumper cars are moving toward each other in opposite directions. Car X is moving at 10 m/s and Car Z at −12 m/s when
nignag [31]
<h2>Given that,</h2>

Mass of two bumper cars, m₁ = m₂ = 125 kg

Initial speed of car X is, u₁ = 10 m/s

Initial speed of car Z is, u₂ = -12 m/s

Final speed of car Z, v₂ = 10 m/s

We need to find the final speed of car X after the collision. Let v₁ is its final speed. Using the conservation of momentum to find it as follows :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v₁ is the final speed of car X.

m_1u_1+m_2u_2-m_1v_1=m_2v_2\\\\m_2v_2=m_1u_1+m_2u_2-m_2v_2\\\\m_1v_1=125\times 10+125\times (-12)-125\times 10\\\\v_1=\dfrac{-1500}{125}\\\\v_1=-12\ m/s

So, car X will move with a velocity of -12 m/s.

3 0
3 years ago
Water falls without splashing at a rate of 0.370 l/s from a height of 2.90 m into a 0.690-kg bucket on a scale. if the bucket is
raketka [301]
<span>R = rate of flow = 0.370 L/s H = height = 2.9 m T= time = 3.9 s V = velocity of water when it hits the bucket = sqrt(2gh) = sqrt(2 x 9.8 x 2.9) =7.539 m/s2 G value = 9.8 m/s2 Wb = weight of bucket = 0.690 kg x 9.8 m/s2 = 6.762 N Wa = weight of accumulated water after 3.9 s Fi = force of impact of water on the bucket S = reading on the scale = Wa + Wb + Fi mass of water accumulated after 3.9 s = R x T = 0.370 x 3.9 = 1.443 L = 1.443 kg Therefore, Wa = 1.443 x 9.8 = 14.1414 N Fi = rate of change of momentum at the impact point = R x V (because R = dm/dt) = 0.37 x 7.539 = 2.78943 N S = 14.1414 + 6.762 + 2.78943 = 23.692 N</span>
8 0
3 years ago
If a car is moving backward and has negative acceleration, what can be said about the speed of the car?
KATRIN_1 [288]
I think its A let me know its wrong or not
4 0
3 years ago
Read 2 more answers
Earth is about 93 million miles from the Sun but only 239,000 miles from the Moon. Likewise, the Sun has a mass that is over 20
Yakvenalex [24]

Answer:

Gravity is dependent on the mass of two bodies and the distance between them. There is a strong gravitational attraction between Earth and the Moon because they’re relatively close to one another. There is a strong gravitational attraction between Earth and the Sun because the Sun is so massive

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2 years ago
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