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Vlad [161]
4 years ago
10

What is the final velocity of a rocket that is traveling at 205 m/s and accelerates at

Physics
1 answer:
-Dominant- [34]4 years ago
7 0

Answer:

70,100 m/s

Explanation:

Given:

v₀ = 205 m/s

a = 8.03 m/s²

Δx = 1750 m

Find: v

v² = v₀² + 2aΔx

v² = (205 m/s)² + 2 (8.03 m/s²) (1750 m)

v = 70,130 m/s

Rounding to three significant figures, the final velocity is 70,100 m/s.

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<h2>Answer: 745.59 nm</h2>

Explanation:

The diffraction angles \theta_{n} when we have a slit divided into n parts are obtained by the following equation:

dsin\theta_{n}=n\lambda (1)

Where:

d is the width of the slit

\lambda is the wavelength of the light  

n is an integer different from zero

Now, the first-order diffraction angle is given when n=1, hence equation (1) becomes:

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We know:

\theta_{1}=34\°

In addition we are told the diffraction grating has 750 slits per mm, this means:

d=\frac{1mm}{750}

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Knowing 1mm=10^{6}nm:

\lambda=745.59nm  >>>This is the wavelength of the light, wich corresponds to red.

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the potential at a point A is 30 V higher than at point B. How much work would you do moving 4.0 C charge from B to A?
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Answer:

True.

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