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sp2606 [1]
3 years ago
9

A pipe open at both ends resonates at a fundamental frequency fopen. When one end is covered and the pipe is again made to reson

ate, the fundamental frequency is fclosed. Which of the following expressions describes how these two resonant frequencies compare?
1.) fclosed = (1/2) fopen

2.) fclosed = (3/2) fopen

3.) none of these

4.) fclosed = fopen

5.) fclosed = 2 fopen
Physics
1 answer:
xz_007 [3.2K]3 years ago
8 0

Answer:

option (1)

Explanation:

fundamental frequency of open pipe, fopen = v/2L

fundamental frequency of closed pipe, f closed = v / 4L

By dividing both of them

f open = 2 x f closed

f open = two times f closed

f closed = 1 / 2 x f open

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Answer:

The speed of the block is 8.2 m/s

Explanation:

Given;

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First, we determine the spring constant based on the principle of conservation of potential energy

¹/₂Kx² = mg(h +x)

¹/₂K(0.25)² = 2.1 x 9.8(5.5 +0.25)

0.03125K = 118.335

K = 118.335 / 0.03125

K = 3786.72 N/m

Total energy stored in the block at rest is only potential energy given as:

E = U = mgh

U = 2.1 x 9.8 x 5.5 = 113.19 J

Work done in compressing the spring to 15.0 cm:

W = ¹/₂Kx² = ¹/₂ (3786.72)(0.15)² = 42.6 J

This is equal to elastic potential energy stored in the spring,

Then, kinetic energy of the spring is given as:

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K.E = 70.59 J

To determine the speed of the block due to this energy:

KE =  ¹/₂mv²

70.59 =  ¹/₂ x 2.1 x v²

70.59 = 1.05v²

v² = 70.59 / 1.05

v² = 67.229

v = √67.229

v = 8.2 m/s

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Answer:

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Answer:

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H = 1/8 g T^2   where T is total time in air  (2 t  = T)

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T = 2 V sin θ / g

T / V = 2 sin θ / g

cos θ = 3 g / 4 (T / V)     from (I)

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