Answer:
alpha=53.56rad/s
a=5784rad/s^2
Explanation:
First of all, we have to compute the time in which point D has a velocity of v=23ft/s (v0=0ft/s)
Now, we can calculate the angular acceleration (w0=0rad/s)
with this value we can compute the angular velocity
and the tangential velocity of point B, and then the acceleration of point B:
hope this helps!!
Answer:
the hypotenuse = 13.78 cm
Ф = 27.44°
θ = 62.56°
explanation:
Answer:
According to the federal aviation regulation for tow pilot, there are three regulatory requirements to be met.
Explanation:
1. The Pilot must hold at least a private pilot certificate with a category rating for powered aircraft.
2. The Pilot must have logged at least 100 hours of pilot-in-command time in the aircraft category.
3. The Pilot must have a logbook endorsed by an authorized instructor who certifies that the person has received ground and flight training in gliders and is proficient in the following;
a. Procedures and techniques of safe towing of gliders.
b. Signal use.
c. Bank maximum angles.
d. Emergency procedures.
<span>when you say a=4.02 i am going to acceleration in m/s^2.
If the acceleration is 4.02 then you take the integral to find the speed.
speed=4.02 t where t is time in seconds.
[4.02(0)+4.02(3.11)]/2=6.2511
[4.02(3.11)+4.02(6.22)]/2=18.7533</span>