A heat engine has a cold reservoir of 250°C and a hot reservoir of 715°C. What is the efficiency of the engine?

2 answers:

6 0

If the heat engine is a perfect carnot cycle engine, then
efficiency = (T2-T1)/T2
where T1=temperature of cold reservoir ( ° K) = 250+273.15 = 523.15
T2=temperature of hot reservoir ( ° K) = 715+273.15 = 988.15

Therefore
efficiency = (T2-T1)/T2 = (988.15-523.15)/988.15 = 0.4706 = 47%

Note: this is the theoretical maximum efficiency of a perfect heat engine. Real-life engines do not achieve this value.

Illusion [34]3 years ago

5 0

The answer is A. 65.0% for plato users, i got 100% on the test :)

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