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Romashka-Z-Leto [24]
3 years ago
12

This chart shows the volumes of four different objects. If the objects all have the same mass, which object is the most dense? O

bject 1 Object 2 Object 3 Object 4
Physics
1 answer:
svet-max [94.6K]3 years ago
3 0

Object 3 on e2020. Hope this helps

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A laser used for many applications of hard surface dental work emits 2780-nm wavelength pulses of variable energy (0-300 mJ) abo
Bess [88]

Answer:

a

    n =  1.119 *10^{18} \ photons

b

  P  =  1.6 \ W

Explanation:

From the question we are told that

    The wavelength is  \lambda  =  2780 nm =  2780 *10^{-9} \ m

     The  energy  is  E =  80 mJ  =  80 *10^{-3} \ J

This energy is mathematically represented as

     E   = \frac{n  *  h *  c }{\lambda }

Where  c is the speed of light with a value  c =  3.0 *10^{8} \ m/s

             h is the Planck's  constant with the value  h  =  6.626 *10^{-34} \ J \cdot s

             n is the number of pulses

So

      n =  \frac{E * \lambda }{h * c }

substituting values

       n =  \frac{80 *10^{-3} *  2780 *10^{-9}}{6.626 *10^{-34} * 3.0 *10^{8} }

       n =  1.119 *10^{18} \ photons

Given that the pulses where emitted 20 times in one second then the period of the pulse is

       T  =  \frac{1}{20}

      T = 0.05 \ s

Hence the average power of photons in one 80-mJ pulse during 1 s is mathematically represented as

       P  =  \frac{E}{T}

substituting values

       P  =  \frac{ 80 *10^{-3}}{0.05}

        P  =  1.6 \ W

6 0
3 years ago
Two blocks of masses mA and mB are connected by a massless spring. The blocks are moved apart, stretching the spring, and subseq
WINSTONCH [101]

Answer:

Part a)

\frac{v_A}{v_B} = -\frac{m_B}{m_A}

Part b)

\frac{K_A}{K_B} = \frac{m_B}{m_A}

Explanation:

Part a)

As we know that initially the two blocks are connected by a spring and initially stretched by some amount

Since the two blocks are at rest initially so its initial momentum is zero

since there is no external force on this system so final momentum is also zero

m_Av_{1i} + m_Bv_{2i} = m_Av_A + m_Bv_B

now for initial position the speed is zero

0 = m_Av_A + m_Bv_B

now we have

\frac{v_A}{v_B} = -\frac{m_B}{m_A}

Part b)

now for ratio of kinetic energy we know that the relation between kinetic energy and momentum is given as

K = \frac{P^2}{2m}

now for the ratio of energy we have

\frac{K_A}{K_B} = \frac{P^2/2m_A}{P^2/2m_B}

since we know that momentum of two blocks are equal in magnitude so we have

now we have

\frac{K_A}{K_B} = \frac{m_B}{m_A}

7 0
3 years ago
Two 3 g bullets are fired with speeds of 40 m/s and 80 m/s. what is the kinetic energy of the first bullet
Licemer1 [7]

The answer is 60. Second is 120.

8 0
3 years ago
During the launch from a board, a diver's angular speed about her center of mass changes from zero to 5.10 rad/s in 170 ms. Her
murzikaleks [220]

Answer:

A(47

B(98

Explanation:

i just did it and got it correct

4 0
3 years ago
Which of the following statements does not represent a benefit of peer relationships? A. Jason and Sean argued over whose turn i
Wewaii [24]
C does not represent a benefit, so that seems most logical.

A) they comprised. 
B) at least ones listening
D) nothings wring with that
3 0
3 years ago
Read 2 more answers
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