Suppose you wish to whirl a pail full of water in a vertical circle at a constant speed without spilling any of its contents (ev
1 answer:
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Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as
= velocity of car A before collision = 0 i -
j
= velocity of car B before collision =
i + 0 j
= velocity of combination after collision = (35.8 Cos31.6) i - (35.8 Sin31.6) j = 30.5 i - 18.8 j
= mass of car A = 1750 kg
= mass of car B = 1450 kg
Using conservation of momentum
+
= (
+
) (
)
(1750) (0 i - j) + (1450) (
i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)
(1450) i - (1750)
j = 97600 i - 60160 j
Comparing the coefficient of "i" and "j" both side
(1450) = 97600 and - (1750)
= - 60160
= 67.3 km/h and
= 34.4 km/
Answer:
the decrease in energy is due to a transformational in internal energy of the body in the rebound.
Explanation:
For this exercise we can calculate the initial and final mechanical energy
Em₀ = U = m g y₁
= U = m g y₂
we look for the variation of the energy
ΔEm = Em_{f} - Em₀
ΔEm = m g (y_{f} -y₀)
ΔEm = m g (0.86 -1.2)
ΔEm = -3.332 m
We can see that there is a decrease in mechanical energy, this is transformed into internal energy of the ball during the impact with the ground, this energy can be formed by several factors such as a part of the friction with the surface, an increase in body temperature or a deformation of the body; there may be a contribution from several of these factors.
In conclusion the decrease in energy is due to a transformational in internal energy of the body in the rebound.
Answer:
Focal length of the eye-lens is 2.0 cm
Explanation:
Given:
An eye-lens system which will follow converging lens (convex lens) sign conventions and knowing that lens-retina distance is the image distance.
Object distance, =
Image distance, =
cm
We have to find the focal length.
Lets say that the focal length is .
Lens Formula:
⇒
Sign-convention:
We will follow the Cartesian coordinate,placing the lens at the origin of the plane, optical center is at now as the object will be towards negative x-axis so it is negative others are on the right side of the origin so they are positive.
Using the lens formula:
⇒
⇒
⇒ <em>...as </em>
a<em>nd there is no </em>
<em> so it is zero only.</em>
⇒ cm
So the focal length is 2.0 cm with two significant figures.