Suppose you wish to whirl a pail full of water in a vertical circle at a constant speed without spilling any of its contents (ev
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Answer:
The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp
Explanation:
<u>Polar moment of Inertia</u>
= 0.14374 in 4
<u>Maximum sustainable torque on the solid circular shaft</u>
=
= 3658.836 lb.in
= lb.ft
= 304.9 lb.ft
<u>Maximum sustainable torque on the tubular shaft</u>
=
= 3334.8 lb.in
= lb.ft
= 277.9 lb.ft
<u>Maximum sustainable power in the solid circular shaft</u>
=
= 4023.061 lb. ft/s
= hp
= 7.315 hp
<u>Maximum sustainable power in the tubular shaft</u>
=
= 3666.804 lb.ft /s
= hp
= 6.667 hp
Answer:
The actual angle is 30°
Explanation:
<h2>Equation of projectile:</h2><h2>y axis:</h2>the velocity is Zero when the projectile reach in the maximum altitude:
When the time is vo/g the projectile are in the middle of the range.
<h2>x axis:</h2>R=Range
**sin(2A)=2sin(A)cos(A)
<h2>The maximum range occurs when A=45°(because sin(90°)=1)</h2><h2>The actual range R'=(2/√3)R:</h2>Let B the actual angle of projectile
2B=60°
B=30°