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VashaNatasha [74]
3 years ago
5

Which of the following statements about nuclear reactions is true?

Chemistry
2 answers:
zalisa [80]3 years ago
8 0
<span>They follow the law of conservation of energy only </span>statements about nuclear reactions is true.
Nesterboy [21]3 years ago
5 0

Answer:

They follow the law of conservation of energy only

Explanation:

Nuclear reaction produces large amount of energy. They are of two types  --

Fission nuclear reaction

Fusion nuclear reaction

Since energy is associated with nuclear reaction, it must follow universal law of conservation of energy.

Law of conservation states that we cannot create energy from anywhere and also we cannot destroy energy. It can only be transferred from one energy form into another energy form.

In the nuclear reaction, energy is obtained from the collisions of the different atoms such as uranium or helium atom, etc.

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3 years ago
Read 2 more answers
CH4 with pressure 1 atm and volume 10 liter at 27°C is passed into a reactor with 20% excess oxygen, how many moles of oxygen is
BaLLatris [955]

Answer : The moles of O_2 left in the products are 0.16 moles.

Explanation :

First we have to calculate the moles of CH_4.

Using ideal gas equation:

PV=nRT

where,

P = pressure of gas = 1 atm

V = volume of gas = 10 L

T = temperature of gas = 27^oC=273+27=300K

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times (10L)=n\times (0.0821L.atm/mol.K)\times (300K)

n=0.406mole

Now we have to calculate the moles of O_2.

The balanced chemical reaction will be:

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that,

As, 1 mole of CH_4 react with 2 moles of O_2

So, 0.406 mole of CH_4 react with 2\times 0.406=0.812 moles of O_2

Now we have to calculate the excess moles of O_2.

O_2 is 20 % excess. That means,

Excess moles of O_2 = \frac{(100 + 20)}{100} × Required moles of O_2

Excess moles of O_2 = 1.2 × Required moles of O_2

Excess moles of O_2 = 1.2 × 0.812 = 0.97 mole

Now we have to calculate the moles of O_2 left in the products.

Moles of O_2 left in the products = Excess moles of O_2 - Required moles of O_2

Moles of O_2 left in the products = 0.97 - 0.812 = 0.16 mole

Therefore, the moles of O_2 left in the products are 0.16 moles.

7 0
3 years ago
How do H3O+ and OH relate to acids, bases and the pH scale?
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Answer: An acid is defined with having more [H₃O+] ions, and a base is defined with having more [OH-] ions. On the pH scale, an acid has a lower pH and a base has a higher pH. With this being said, the lower the pH, the more [H₃O+] ions are present and the higher the pH, the more [OH-] ions are present.

Explanation:

I hope this helps!! Pls give brainliest!! :)

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A science fair volcano bubbles and fizzes. what is taking place?
vaieri [72.5K]
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Answer:

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