1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kakasveta [241]
3 years ago
13

Some oxygen gas takes up a volume of 2.00 liters at 0.99 atm and 273 K. Its volume doubles and its temperature decreases to 137

K. What is the final pressure of the gas?
A.cannot be ddtermined
B.0.25 atm
C.0.98 atm
D.3.9 atm
Chemistry
2 answers:
nataly862011 [7]3 years ago
5 0

Answer:

The answer to your question is : letter B. 0.25 atm

Explanation:

To solve this problem we need to use the combined gas law:

    <u>P₁V₁</u>   =    <u>P₂V₂</u>

      T₁              T₂

Data

P1 = 0.99 atm  V1 = 2 l  T1 = 273K

P2 = ?               V2 = 4 l   T2 = 137K

Now, the clear P2 from the equation and we get

       P2 = P1V1T2 / T1V2

Substitution         P2 = (2 x 0.99 x 137)/(273 x 4)

       P2 = 271.26 / 1092

Result       P2 = 0.248 atm ≈ 0.25 atm

fredd [130]3 years ago
5 0

Answer : The correct option is, (B) 0.25 atm

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.99 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 2.00 L

V_2 = final volume of gas = 2\times V_1=2\times 2.00L=4.00L

T_1 = initial temperature of gas = 273 K

T_2 = final temperature of gas = 137 K

Now put all the given values in the above equation, we get:

\frac{0.99atm\times 2.00L}{273K}=\frac{P_2\times 4.00L}{137K}

P_2=0.25atm

Therefore, the final pressure of the gas is 0.25 atm.

You might be interested in
What is the number of moles in 526 L O2 at STP?
Katena32 [7]
526 L O2 x 1 mol O2 / 22.4 L = 23.5 mol O2
3 0
3 years ago
Read 2 more answers
19) The nuclear symbol of helium,
Amiraneli [1.4K]

Answer:

Alpha particle

Explanation:

The helium symbol is also used to represent he alpha particles.

For example:

The americium with atomic wight  224 undergo alpha decay and produce

₉₃Np²³⁷ . The alpha particle emitted is also called helium nuclei. During this decay some gamma radiations also produce as a byproduct.

₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴

Properties of alpha radiation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

4 0
3 years ago
SCIENCEEEE!!!! HELPPPPP MEEEE OUTTTT!!!!
krok68 [10]
B and e

first we need to balance the NH3 hence first we do E and multiplying the coefficient by 2. that will leave us with N2+H2–>2NH3.
N2 and H2 is balanced and now all that is left to do is the balance H2 by 3 as there is 6H on RHS hence we need 6H on LHS
3 0
3 years ago
When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°
dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.30^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant =  

m= molality = \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579

8.30^0C=1\times K_f\times 0.579

K_f=14.3^0C/m

Let Mass of solute (KBr) = x g

8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}

x=58.2g

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

7 0
2 years ago
Identify each of the following as a representative element or a transition element:
charle [14.2K]
The correct answer is B. Platinum is the transition element among the choices. The elements belonging to this group are those having a partially filled d or f subshell. It usually refers to the d-block transition elements of the periodic table.
3 0
3 years ago
Other questions:
  • Which quantity is used to generate the error bars on a graph?
    11·1 answer
  • You have an evacuated container of fixed volume and known mass and introduce a known mass of a gas sample. measuring the pressur
    13·1 answer
  • HURRY ⚠️<br> How many Chlorine atoms in 2HCI?<br> Hiw many Hydrogen atoms are in 2HCl?
    12·2 answers
  • Adding energy to a solid bar of gold may result in which of the following outcomes
    6·1 answer
  • What is the mass of oxygen in 10g of water
    14·1 answer
  • What is the half-life of Technetium-99 if a 200 gram sample decays to 50 grams in 639,000 years?
    5·1 answer
  • The conversion of large hydrocarbon molecules into smaller molecules is known as:
    9·1 answer
  • The process shown was used by Mendel during his experiments. What is the process called?​
    12·1 answer
  • *
    11·1 answer
  • How many moles are in 8.32 × × times 10^24 molecules of co2?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!