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3 years ago

If it takes 38.70cm³ of 1.90 M NaOH to neutralize 10.30cm³ of H2SO4 in a battery, What's the Molarity of the H2SO4 ?

Chemistry

2 answers:

meriva3 years ago

8 0

Answer:

Volume of acid Va = 38.70cm3,

Concentration of acid Ca = 1.90M

Volume of Base Vb = 10.30cm3

Concentration of base Cb = ?

Equation of the reaction

H2SO4 + 2NaOH = Na2SO4 + 2H2O

No of mole of acid Na = 1

No of mole of base Nb = 2

CaVa/CbVb = Na/Nb

Cb = CaVaNb/VbNa

Cb = 1.9*38.7*2/10.30*1

Cb = 14.2777M

Explanation:

arlik [135]3 years ago

3 0

Answer: 3.57M

Explanation:Please see attachment for explanation

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Please help with chemistry question... It would help me tremendously and if you can, please show work :)?

Alexxandr [17]

Answer:

5.06 atm

Explanation:

Step 1:

Data obtained from the question. This includes:

Mass of S2O = 175g

Volume (V) = 16600 mL

Temperature (T) = 195°C

Pressure (P)

Step 2:

Determination of the number of mole of S2O in 175g of S2O.

Mass of S2O = 175g

Molar Mass of S2O = (32x2) + 16 = 64 + 16 = 80g/mol

Number of mole of S2O =.?

Number of mole = Mass/Molar Mass

Number of mole of S2O = 175/80

Number of mole of S2O = 2.1875 moles

Step 3:

Conversion to appropriate units.

It is essential to always express the various variables in the right units of measurement in order to obtain the desired answer in the right units.

For volume:

1000mL = 1L

Therefore, 16600mL = 16600/1000 = 16.6L

For temperature:

Temperature (Kelvin) = temperature (celsius) + 273

Temperature (celsius) = 195°C

Temperature (Kelvin) = 195°C + 273 = 468K

Step 4:

Determination of the pressure.

The pressure can be obtained by the application of the ideal gas equation. This is illustrated below:

Volume (V) = 16.6L

Temperature (T) = 468K

Number of mole (n) = 2.1875 moles

Gas constant (R) = 0.082atm.L/Kmol

Pressure (P) =

PV = nRT

P x 16.6 = 2.1875 x 0.082 x 468

Divide both side by 16.6

P = (2.1875 x 0.082 x 468) /16.6

P = 5.06 atm

Therefore, the pressure is 5.06 atm

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3 years ago

For alpha decay to cause a loss in mass, such as that in the uranium 238 conversion to thorium 234, what must the atomic weight

Aleonysh [2.5K]

Explanation:

Reaction equation showing alpha decay in Uranium-238 is as follows.

$^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He$

It is known that an alpha particle is basically a helium nucleus and it contains 2 protons and 2 neutrons.

Symbol of an alpha particle is $^{4}_{2}\alpha$ .

As atomic mass or weight is the sum of total number of protons and neutrons present in an atom.

Hence, the atomic weight of the alpha particle is (2 + 2) = 4.

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3 years ago

0.785 moles of N2,fill a balloon at 1.5 atm and 301 K.<br> What is the volume of the balloon?

Tcecarenko [31]

Answer:

V = 12.93 L

Explanation:

Given data:

Number of moles = 0.785 mol

Pressure of balloon = 1.5 atm

Temperature = 301 K

Volume of balloon = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will put the values.

V = nRT/P

V = 0.785 mol × 0.0821 atm.L/ mol.K × 301 K / 1.5 atm

V = 19.4 L /1.5

V = 12.93 L

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3 years ago

Density of a piece of wood that has a measurement of 24 cm3 and 768 g

Brut [27]

Answer:

<h3>The answer is 32 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 768 g

volume = 24 cm³

We have

$density = \frac{768}{24} \\$

We have the final answer as

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Answer:

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If it takes 38.70cm³ of 1.90 M NaOH to neutralize 10.30cm³ of H2SO4 in a battery, What's the Molarity of the H2SO4 ?​

If it takes 38.70cm³ of 1.90 M NaOH to neutralize 10.30cm³ of H2SO4 in a battery, What's the Molarity of the H2SO4 ?