If it takes 38.70cm³ of 1.90 M NaOH to neutralize 10.30cm³ of H2SO4 in a battery, What's the Molarity of the H2SO4 ?
2 answers:
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Answer:
0.7802 M
Explanation:
<u>Data:</u>
- V (volume) = 100.0 mL → V = 0.1000 L
- m (mass) = 6.631 g → n = 0.07802 mol
<u>Wanted: </u>
- M (Molarity)
<u>Equation: </u>
M =
<u>Solution:</u>
1. Convert mL to L:
- V = 100.0 mL x
= 0.1000 L
2. Convert g to mol:
- n =
= 0.07802 mol
3. Molarity Equation:
- M =
= 0.7802 M