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SVEN [57.7K]
2 years ago
8

Write a reflection about your learning in this unit. Your reflection should be at least 3 sentences. Use the following sentence

starters as a guide.
• I feel confident that I can build a model of the food chain because...

• The food chain impacts my daily life because...

• I can use evidence to show plant matter does not come from soil by...​
Chemistry
1 answer:
Vera_Pavlovna [14]2 years ago
5 0

Answer:

This unit has encouraged a deeper understanding of the world and it's guiding principles. While it was initially challenging for me to determine if a change was physical or chemical, this unit provided me with the information necessary to determine the type. With this knowledge, I can now interrelate with other properties and believe that this new ability will assist in future units as well. Thank you!

Explanation:

You might be interested in
A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0
3 years ago
Read 2 more answers
2. To what volume will you have to dilute 20.0 ml of a 8 M HCl solution to make a 0.35 M
GrogVix [38]

Answer:

You need to dilute 8 M HCl to 0.35 M to make 457 mL.

Explanation:

Use the equation M₁V₁=M₂V₂

Convert the mL to L : 20 mL= 0.02 L

8 M x 0.02 L = 0.35 M x V₂

V₂ = 0.4571429 L = 457 mL

3 0
3 years ago
What is the product of the unbalanced equation below?
Stolb23 [73]

Answer:

D

Explanation:

The answer is D. I'm not sure that it is a solid. I don't think it is a ppte, which is the only way it can be a true solid. It is ionic if the reaction is taking place in water and there is someway to start the reaction. Be that as it may, the internal balace numbers of the chemical produced is the only possible answer. The balanced eq;uatioon is

2Al + 3Br2 ==> 2AlBr3

3 0
3 years ago
If 12 moles of Al2O3<br> are produced, how many moles of aluminum reacted?
Mandarinka [93]

Answer:

if 12 moles are produced then it came 24 moles of Al(OH)3

Explanation:

6 0
2 years ago
A filament for a light bulb needs to conduct electricity. Which of the elements listed below might be useful as a light bulb fil
horrorfan [7]

Answer:

A. tungsten

Explanation:

Tungsten is a material which high melting point ie. does not melt easily incase of high temperature

8 0
3 years ago
Read 2 more answers
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