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3 years ago

Select the correct answer.

Chemistry

1 answer:

matrenka [14]3 years ago

5 0

Answer:

At equilibrium the rate of the forward reaction is equal to the rate of the backward reaction.

When the product of a reaction at equilibrium is increased the equilibrium will shift left or to the reactant side. As a result the excess product will get converted to reactant. This is in accordance to Le Chatelier's principle.

Le Chatelier's principle states that when a system is subjected to stress the equilibrium will shift in a direction to minimize effect of the stress.

Thus the products added to the system at equilibrium will make the equilibrium shift to the reactant side, the rate of the reverse or backward reaction will increase.

Explanation:

Hope This Helps Amigo!

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What kind of reaction is this?

zheka24 [161]

Answer:

Single replacement

Explanation:

Chemical equation:

2Al(NO₃)₃ + 3Ca → 3Ca(NO₃)₂ + 2Al

Single replacement:

It is the reaction in which one elements replace the other element in compound.

AB + C → AC + B

All other options are incorrect because,

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AD +CB

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

Decomposition reaction:

It is the reaction in which one reactant is break down into two or more product.

AB → A + B

Combustion reaction:

Reaction in substance react with oxygen and form carbon dioxide and water.

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3 years ago

A gas has a volume of 543 ml. at a temperature of 75.0°C. What volume will the gas occupy at 20.2°C?

alexandr1967 [171]

Answer:

V₂ = 457.49 mL

Explanation:

Given that,

Initial volume, $V_1=543\ mL$

Initial temperature, $T_1=75^{\circ} C=75+273=348\ K$

Final temperature, $T_2=20.2^{\circ} C=20.2+273=293.2\ K$

We need to find the final volume of the gas. The relation between the volume and the temperature of the gas is given by :

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Put the respected values,

$V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{543\times 293.2}{348}\\\\V_2=457.49\ mL$

So, the final volume of the gas is equal to 457.49 mL.

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