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sasho [114]
3 years ago
8

Given 1.00 maria = 2.34 how many liters equal 13.5 maria

Chemistry
1 answer:
saw5 [17]3 years ago
4 0

Answer:

31.6 L would be equal to 13.5 MARIA. 31.6 L would be equal to 13.5 MARIA

Explanation:

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kondor19780726 [428]

The mass of the blood is 5.8 kg.

<em>V</em> = 5.5 L = 5500 mL

Mass = 5500 mL × (1.06 g/1 mL) = 5800 g = 5.8 kg

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8 0
3 years ago
A sample of methane collected when the temp was 30 C mmHg measures 398 mL. What would be the volume of the sample at -5 C and 61
Levart [38]
<h2>Question </h2>

A sample of methane collected when the temp was 30 C and 760mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure

<h2>Answer:</h2>

434.32mL

<h2>Explanation:</h2>

Using the combined gas law:

\frac{PV}{T} = k

Where;

P = Pressure

V = Volume

T = Temperature

k = constant.

It can be deduced that:

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} = k           ---------------------(i)

Where:

P₁ and P₂ are the initial and final pressures of the given gas

V₁ and V₂ are the initial and final volumes of the given gas

T₁ and T₂ are the initial and final temperatures of the gas.

<em>From the question:</em>

the gas is methane

P₁  = 760mmHg

P₂ = 616mmHg

V₁ = 398mL

V₂ = ?

T₁ = 30°C = (30 +273)K = 303K

T₂ = -5°C = (-5 +273)K = 268K

Substitute these values into equation (i) as follows;

\frac{760*398}{303} = \frac{616*V_2}{268}

Solve for V₂

V₂ = \frac{760*398*268}{616*303}

V₂ = 434.32mL

Therefore, the volume of the sample at -5C and 616mmHg pressure is 434.32mL

5 0
3 years ago
Why can't all mixtures be classified as solutions?
shusha [124]
D. Not all mixtures are heterogeneous
7 0
3 years ago
Predict the missing component of each reaction.<br> ? + 2NaBr → 2NaC1+Brz<br> онСІ<br> ch<br> Na
EastWind [94]

Answer:

Cl2.

Explanation:

? + 2NaBr → 2NaC1l+ Br2

Note that the element Cl (chlorine) is missing from the left side.

The answer is Cl2  (to balance the equation it requires 2 Cl's).

5 0
3 years ago
Read 2 more answers
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