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Virty [35]
3 years ago
8

65. A pizza, heated to a temperature of 400°F, is taken out of an oven and placed in a 75°F room at timet= 0 minutes. The temper

ature of the pizza is changing such that its decay constant, k, is 0.325. At what time is the temperature of the pizza 150°F and, therefore, safe to eat? Give your answer in minutes.
Mathematics
1 answer:
Amanda [17]3 years ago
4 0

Answer:

769MIN

Step-by-step explanation:

Hello!

To solve this problem we must use the straight line equation, this equation is as follows

Y=mx+b

where

X= time

Y=Temperature

b= intercept with the y axis when x = 0, therefore y = 400

m=k= temperature decrease with respect to time=-0.325

now we replace the values ​​in the equation of the line

Y=-0.325X+400

Now we find the time it takes for the pizza to reach 150 F replacing in the equation and finding X

150=-0.325X+400

150-400=-0.325X+

X=\frac{150-400}{-0.325} =769MIN

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