Answer:
The distance between first-order and second-order bright fringes is 12.66mm.
Explanation:
The physicist Thomas Young establishes through its double slit experiment a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.
(1)
Where
is the distance between two adjacent maxima, L is the distance of the screen from the slits,
is the wavelength and d is the separation between the slits.
The values for this particular case are:



Notice that is necessary to express L and
in units of milimeters.
⇒ 
⇒ 
Finally, equation 1 can be used:
Hence, the distance between first-order and second-order bright fringes is 12.66mm.
<span>when two hydrogen atoms approach each other the potential energy of the combination becomes lower and lower until it reaches a minimum value of -436 kl/mol at a distance of 75 pm</span>
Answer:
Total time = 10.667 seconds
Explanation:
For the first 12m
V² = u² + 2as
10.5² = 0² + 2a(12)
110.25 = 24a
a = 4.59375 m/s²
V = u + at
10.5 = 0 + 4.59375t
t = 10.5/4.59375
t = 2.286 seconds
For the remaining race
100-12 = 88m
He travels at a constant speed for 88m
S = ut + 1/2(at²)
But a = 0
S = ut
88= 10.5t
t = 88/10.5
t = 8.38.seconds
Total time = 2.286 + 8.381
Total time = 10.667 seconds