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4 years ago

14

Describe and explain the potential energy changes that occur during the formation of a covalent bond

1 answer:

Yanka [14]4 years ago

8 0

<span>when two hydrogen atoms approach each other the potential energy of the combination becomes lower and lower until it reaches a minimum value of -436 kl/mol at a distance of 75 pm</span>

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If a wave has a speed of 362 m/s and a period of 4.17 ms, its wavelength is closest to

Dominik [7]

Answer:

Option A (1.51 m) is the appropriate option.

Explanation:

The given values are:

Speed of wave,

= 362 m/s

Period,

= 4.17

Now,

⇒ $v=\frac{\lambda}{T}$

then,

⇒ $\lambda=vT$

⇒ $= 362\times 4.17\times 10^{-3}$

⇒ $=1.51 \ m$

3 0

3 years ago

A bullet with a mass ????b=13.5 g is fired into a block of wood at velocity ????b=249. The block is attached to a spring that ha

larisa86 [58]

Answer:

$M = 0.436 kg$

Explanation:

As per energy conservation we can say that energy stored in the spring at the position of maximum compression must be equal to the kinetic energy of bullet and block system

so here we have

$\frac{1}{2}(m + M)v^2 = \frac{1}{2} kx^2$

here we know that

k = 205 N/m

x = 35 cm

$\frac{1}{2}(m + M)v^2 = \frac{1}{2}(205)(0.35)^2$

now by momentum conservation we know that

$mv_o = (m + M)v$

$v = \frac{m}{m + M} v_o$

now plug in all values in it

$v = \frac{0.0135}{0.0135 + M}(249)$

now from above equation

$\frac{1}{2}(0.0135 + M)( \frac{0.0135}{0.0135 + M}(249))^2 = 12.56$

$\frac{5.65}{0.0135 + M} = 12.56$

by solving above equation we have

$M = 0.436 kg$

3 0

4 years ago

A rifle fires a 2.10 x 10^-2 kg pellet straight upward, because the pellet rests on a compressed spring when the trigger is is p

yKpoI14uk [10]

m = mass of pellet = 2.10 x 10⁻² kg

x = compression of spring at the time launch = 9.10 x 10⁻² m

h = height gained by the pellet above the initial position = 6.10 m

k = spring constant

using conservation of energy

spring potential energy = gravitational potential energy of pellet

(0.5) k x² = m g h

inserting the values

(0.5) k (9.10 x 10⁻²)² = (2.10 x 10⁻²) (9.8) (6.10)

k = 303.2 N/m

4 0

3 years ago

It takes 50 seconds for Tyler to do 450 Joules of work. How much power did Tyler use?

Bogdan [553]

Power=work/time
So,
Power =450/50=9watts

8 0

3 years ago

Read 2 more answers

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 54.0 cm. The explorer finds that

Natasha2012 [34]

Answer:

g = 11.2 m/s²

Explanation:

First, we will calculate the time period of the pendulum:

$T = \frac{t}{n}$

where,

T = Time period = ?

t = time taken = 135 s

n = no. of swings in given time = 98

Therefore,

$T = \frac{135\ s}{98}$

T = 1.38 s

Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

$T = 2\pi \sqrt{\frac{l}{g}}$

where,

l = length of pendulum = 54 cm = 0.54 m

g = acceleration due to gravity on the planet = ?

Therefore,

$(1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}$

<u>g = 11.2 m/s²</u>

3 0

3 years ago