Answer:
31.4 inches
Step-by-step explanation:
If a circle is inscribed in a square then diameter of circle inscribed is same as side as of square.
In the given problem it is given that side of square is 10 inches.
So diameter of circle inscribed is 10 inches
we know radius of circle is half of diameter of circle
Thus, radius of circle inscribed = diameter of circle/2 = 10/2 = 5inches.
Expression to calculate circumference of circle is given by 
where r is the radius of circle.
Thus circumference of circle inscribed is
Thus, circumference of circle inscribed is 31.4 inches
So when you have one of these, it’s just asking you so solve it as if x were 6 (as you see where the x in f(x) is replaced with a 6.
so you’d sub x for 6
giving you:
4 x (6)
which = 24
hope that makes sense :)
the assumption here being that both lines JH and FH are tangent lines to the circle, if that's the case the external angle of 34° is the angle made by the equal tangents, meaning the triangle is an isosceles with twin sides.
In an isosceles triangle the twin sides make also twin angles, so the angles at J and F are twins, and they'd be 180° - 34° = 146° total, since they're twins, each one takes half, or 73°.
Answer:
Required difference = 270/19 km
Step-by-step explanation:
If we consider the AP of distances to be
a, a + r, a + 2r, ..., a + 19r,
where a is the distance of the nearest location from the port and r is the difference between any two successive location.
Given that,
a + 19r = 300 .....(1)
a = 30 ..... (2)
Using (2), from (1), we get
30 + 19r = 300
or, 19r = 300 - 30
or, 19r = 270
or, r = 270/19
Therefore the distance between any two successive location is 270/19 km.
The answer is 1.00 m. Hope this helps.
