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3 years ago

What is the percentage… b of sugar in the syrup made of 10 kg of water and 4 kg of sugar?

Mathematics

2 answers:

Artist 52 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

4 kg - weight of sugar

10 kg - mass of water

4kg + 10kg = 14kg - weight of the syrup

$\dfrac{4kg}{14kg}=\dfrac{2}{7}$

The sugar is 2/7 of the weight of the syrup.

Convert to the percentage:

$\dfrac{2}{7}=\dfrac{2}{7}\cdot100\%=\dfrac{200}{7}\%=28\dfrac{4}{7}\%\aaprox29\%$

ozzi3 years ago

4 0

Answer:

200/7

Step-by-step explanation:

4 kg - weight of sugar

10 kg - mass of water

4kg + 10kg = 14kg - weight of the syrup

The sugar is 2/7 of the weight of the syrup.

Convert to the percentage: 28 and 4/7 percent

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Step-by-step explanation:

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The transformed function has the following:

Negative: reflection across the x-axis

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