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3 years ago

What is the average velocity of a car that travels 30 kilometers due west in 0.50 hour

1 answer:

7 0

Divide the distance traveled (0.30 km) by the travel time (0.50 hrs) and get the speed in km/hr. The direction is due west. 60 km/hr west

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A heated piece of metal cools according to the function c(x) = (.5)^(x _ 11), where x is measured in hours. A device is added th

Agata [3.3K]

You just need to replace x with 5 in each function

.5^5 - 11
-5-3

.5 ^-6
-8

64 - 8 = 56 A Celcius

Hope this helps

3 0

3 years ago

Read 2 more answers

N experiment is performed in deep space with two uniform spheres, one with mass 27.0 and the other with mass 107.0 . They have e

Reptile [31]

Answer:

Explanation:

Apply the law of conservation of energy

$KE_i+PE_i=KE_f+PE_f$

$Gm_1m_2[\frac{1}{r_f} -\frac{1}{r_1} ]=\frac{1}{2} (m_1v_1^2+m_2v_2^2)$

from the law of conservation of the linear momentum

$m_1v_1=m_2v_2$

Therefore,

$Gm_1m_2[\frac{1}{r_f} -\frac{1}{r_1} ]=\frac{1}{2} (m_1v_1^2+m_2v_2^2)$

$=\frac{1}{2} [m_1v_1^2+m_2[\frac{m_1v_1}{m_2} ]^2]\\\\=\frac{1}{2} [m_1v_1^2+\frac{m_1^2v_1^2}{m_2} ]\\\\=\frac{m_1v_1^2}{2} [\frac{m_1+m_2}{m_2} ]$

$v_1^2=[\frac{2Gm_2^2}{m_1+m_2} ][\frac{1}{r_f} -\frac{1}{r_1} ]$

Substitute the values in the above result

$v_1^2=[\frac{2Gm_2^2}{m_1+m_2} ][\frac{1}{r_f} -\frac{1}{r_1} ]$

$=[\frac{2(6.67\times 10^-^1^1)(107)^2}{27+107} ][\frac{1}{26} -\frac{1}{41}] \\\\=1.6038\times 10^-^1^0\\\\v_1=\sqrt{1.6038\times 106-^1^0} \\\\=1.2664 \times 10^-^5m/s$

B) the speed of the sphere with mass 107.0 kg is

$v_2=\frac{m_1v_1}{m_2}$

$=[\frac{27}{107} ](1.2664 \times 10^-^5)\\\\=3.195\times 10^-^6m/s$

C) the magnitude of the relative velocity with which one sphere is

$v_r=v_1+v_2\\\\=1.2664\times 10^-^5+3.195\times10^-^6\\\\=15.859\times10^-^6m/s$

D) the distance of the centre is proportional to the acceleration

$\frac{x_1}{x_2} =\frac{a_1}{a_2} \\\\=\frac{m_2}{m_1} \\\\=3.962$

Thus,

$x_1=3.962x_2$

and

$x_2=0.252x_1$

When the sphere make contact with eachother

Therefore,

$x_1+x_2+2r=41\\x_1+0,252x_1+2r=41\\1.252x_1+2r=41\\x_1=32.747-1.597r$

And

$x_1+x_2+2r=41\\3.962x_2+x_2+2r+41\\4.962x_2+2r=41\\x_2=8.262-0.403r$

The point of contact of the sphere is

$32.747-1.597r=8.262-0.403r\\\\r=\frac{24.485}{1.194} \\\\=20.506m$

3 0

3 years ago

What describes the movement of a fluid during convection?

damaskus [11]

Convection is the movement<span> of groups of molecules within </span>fluids<span> such as gases and liquids, including molten rock (rheid).</span>

5 0

3 years ago

What did you include in your description? Check all that apply

Alexeev081 [22]

I included things
Hope this helps!

7 0

3 years ago

The roller coaster is designed according to safety regulations that prohibit the speed of the car from exceeding 20 m/s. find th

hram777 [196]

maximum allowed value of the speed in roller coaster is given as

$v = 20 m/s$

now from kinematics we can say

$v^2 - v_i^2 = 2 a s$

here initial speed will be

$v_i = 0$

acceleration is due to gravity

$a = 9.8 m/s^2$

now we can use this to find the height

$20^2 - 0^2 = 2 * 9.8* h$

$400 = 19.6 *h$

$h = 20.4 m$

so maximum allowed height will be 20.4 m

4 0

3 years ago