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Elis [28]
3 years ago
15

What is the difference between three types of mechanical waves?

Physics
2 answers:
Amanda [17]3 years ago
8 0

<u>Answer:</u>

There are three kinds of mechanical waves depending upon the direction in which they travel or propagate through the medium.

(i) Longitudinal waves

(ii) Transverse waves

(iii) Surface waves

In transverse waves, the particles tend to move in a direction at right angles to the waves whereas in longitudinal waves, they move in parallel direction to each other. When it comes to surface waves they lie in circular motion.

Marta_Voda [28]3 years ago
5 0

Answer:

In longitudinal waves, particles travel in the direction parallel to that of the wave motion where as in transverse waves, particles move perpendicular to the direction of the wave motion and in surface waves, particles in the medium move in a circular motion.A good example of longitudinal waves is sound waves. Vibrating a string on the ground can serve as an example of transverse wave.For surface waves, the ocean waves travelling on the surface can illustrate the cicular movement of particles in the water.

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What caused the blackout in Canada?
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Answer:

Hello, the tripping of a 230-kilovolt transmission line.

Explanation:

the tripping of a 230-kilovolt transmission line near Ontario, Canada, at 5:16 p.m., which caused several other heavily loaded lines also to fail. Hopefully this helps you find what your looking for!.

7 0
3 years ago
Which of Newton's laws of motion describes the motion of an object that has a net<br> force of ON?
algol [13]

Newton's first and second laws of motion both do, but I think the one you're looking for is: <em>The First Law of Motion</em>.  That description is a little more direct.

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3 0
2 years ago
A 0.2 kg hockey park is sliding along the eyes with an initial velocity of -10 m/s when a player strikes it with his stick, caus
babunello [35]

Answer:

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

Explanation:

The Impulse Theorem states that the impulse experimented by the hockey park is equal to the vectorial change in its linear momentum, that is:

I = m\cdot (\vec{v}_{2} - \vec{v_{1}}) (1)

Where:

I - Impulse, in kilogram-meters per second.

m - Mass, in kilograms.

\vec{v_{1}} - Initial velocity of the hockey park, in meters per second.

\vec{v_{2}} - Final velocity of the hockey park, in meters per second.

If we know that m = 0.2\,kg, \vec{v}_{1} = -10\,\hat{i}\,\left[\frac{m}{s}\right] and \vec {v_{2}} = 25\,\hat{i}\,\left[\frac{m}{s} \right], then the impulse applied by the stick to the park is approximately:

I = (0.2\,kg)\cdot \left(35\,\hat{i}\right)\,\left[\frac{m}{s} \right]

I = 7\,\hat{i}\,\left[\frac{kg\cdot m}{s} \right]

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

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