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Elis [28]
3 years ago
15

What is the difference between three types of mechanical waves?

Physics
2 answers:
Amanda [17]3 years ago
8 0

<u>Answer:</u>

There are three kinds of mechanical waves depending upon the direction in which they travel or propagate through the medium.

(i) Longitudinal waves

(ii) Transverse waves

(iii) Surface waves

In transverse waves, the particles tend to move in a direction at right angles to the waves whereas in longitudinal waves, they move in parallel direction to each other. When it comes to surface waves they lie in circular motion.

Marta_Voda [28]3 years ago
5 0

Answer:

In longitudinal waves, particles travel in the direction parallel to that of the wave motion where as in transverse waves, particles move perpendicular to the direction of the wave motion and in surface waves, particles in the medium move in a circular motion.A good example of longitudinal waves is sound waves. Vibrating a string on the ground can serve as an example of transverse wave.For surface waves, the ocean waves travelling on the surface can illustrate the cicular movement of particles in the water.

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A 52 kg and a 95 kg skydiver jump from an airplane at an altitude of 4750 m, both falling in the pike position. Assume all value
Scilla [17]

Answer: 52 kg skydiver: 9.09 m/s and 522.55 s

              95 kg skydiver: 12.3 m/s and 386.2 s

Explanation: <u>Drag</u> <u>Force</u> is an opposite force when an object is moving in a fluid.

For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the <u>Terminal</u> <u>Velocity</u>.

Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:

F_{G}=F_{D}

mg=\frac{1}{2}C \rho Av_{T}^{2}

v_{T}=\sqrt{\frac{2mg}{\rho CA} }

where

m is mass in kg

g is acceleration due to gravitational force in m/s²

ρ is density of the fluid in kg/m³

C is drag coefficient

A is area of the object in the fluid in m²

Calculating:

The 52kg skydiver has terminal velocity of:

v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }

v_{T}= 9.09

The 95kg skydiver's terminal velocity is

v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }

v_{T}= 12.3

The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.

The time each one will reach the floor will be:

52 kg at 9.09 m/s:

t=\frac{4750}{9.09}

t = 522.5

95 kg at 12.3 m/s:

t=\frac{4750}{12.3}

t = 386.2

The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.

3 0
3 years ago
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