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suter [353]
4 years ago
6

Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this mod

el compare to a model for the force of gravity?
Physics
2 answers:
kykrilka [37]4 years ago
7 0

Answer:

The answer is C

Explanation:

I did it on usatestprep and got it right

aivan3 [116]4 years ago
6 0

Answer:

As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

Gravitation Force=\frac{Gm_{1}m_{2} }{r^{2}}

Coulombs's Law= \frac{Kq_{1}q_{2} }{r^{2}}

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A particle is located on the x axis 4.9 m from the origin. A force of 38 N, directed 30° above the x axis in the x-y plane, acts
Juli2301 [7.4K]

Answer:

Torque is 93 Nm anticlockwise.

Explanation:

We have value of torque is cross product of position vector and force vector.

A force of 38 N, directed 30° above the x axis in the x-y plane.

        Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j

A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.

Position vector, r = 4.9 i

Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm

So Torque is 93 Nm anticlockwise.

7 0
3 years ago
Which of the following statements is false? In solids, the particles do not move around or change position; they can only vibrat
Andrew [12]
"<span>The particles of gases are the least capable of moving around"
its the opposite, gases have the most capability to move around
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8 0
3 years ago
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Scientists are told to doubt everything and not believe anything that is not provable. Is this a strength or weakness of science
ioda
A strength because everything has evidence
4 0
3 years ago
A rocket is launched with a velocity of 30 m/s at 40° to the horizontal. How far will it travel horizontally? 0 3.01 m 0 90.54 m
Lapatulllka [165]

Answer:

The horizontal distance traveled by the rocket is 90.46 m

Explanation:

Given;

initial velocity of the rocket, u = 30 m/s

angle of projection, θ = 40°

the horizontal distance traveled by the rocket = ?

The horizontal distance traveled by the rocket is given by the range of the projectile.

The range of the projectile is given as;

R = \frac{u^2Sin(2\theta)}{g}\\\\R = \frac{(30)^2sin(80^0)}{9.8}\\\\R = 90.46 \ m

Therefore, the horizontal distance traveled by the rocket is 90.46 m

The closest answer in the given options is 90.54 m

3 0
3 years ago
A conductor is formed into a loop that encloses an area of 1.0 m2. The loop is orientedat a 30.0° angle with the xy-plane. A var
ivolga24 [154]

Answer:

29 T/s

Explanation:

Given:

Area enclosed by loop, A = 1 m²

Maximum induced emf, e = 25.0 V

loop is oriented at an angle 30° with the x-y plane.

varying magnetic field is oriented parallel to z-axis.

we have to find \frac{dB}{dt}_{max}

Induced emf is given by:

e =-A.cos\theta .\frac{dB}{dt}\\ \Rightarrow \frac{dB}{dt}=-\frac{e}{Acos\theta} = -\frac{25}{1\times cos30^o} = -28.86T/s≈29T/s

3 0
3 years ago
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