Answer:
Torque is 93 Nm anticlockwise.
Explanation:
We have value of torque is cross product of position vector and force vector.
A force of 38 N, directed 30° above the x axis in the x-y plane.
Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j
A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.
Position vector, r = 4.9 i
Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm
So Torque is 93 Nm anticlockwise.
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its the opposite, gases have the most capability to move around
</span>
A strength because everything has evidence
Answer:
The horizontal distance traveled by the rocket is 90.46 m
Explanation:
Given;
initial velocity of the rocket, u = 30 m/s
angle of projection, θ = 40°
the horizontal distance traveled by the rocket = ?
The horizontal distance traveled by the rocket is given by the range of the projectile.
The range of the projectile is given as;

Therefore, the horizontal distance traveled by the rocket is 90.46 m
The closest answer in the given options is 90.54 m
Answer:
29 T/s
Explanation:
Given:
Area enclosed by loop, A = 1 m²
Maximum induced emf, e = 25.0 V
loop is oriented at an angle 30° with the x-y plane.
varying magnetic field is oriented parallel to z-axis.
we have to find 
Induced emf is given by:
≈29T/s