Answer:
1) The reaction rate is double with respect to that reactant
Explanation:
Hello,
By considering the rate law:
If we double the reactant A concentration, by definition, the rate will be doubled as well since the 
power is one (order 1), this could be proved just by checking it out in the rate law.
Best regards.
Option d: copper.
Because copper is an element, not a mixture.
Answer:
12.32 L.
Explanation:
The following data were obtained from the question:
Mass of CH4 = 8.80 g
Volume of CH4 =?
Next, we shall determine the number of mole in 8.80 g of CH4. This can be obtained as follow:
Mass of CH4 = 8.80 g
Molar mass of CH4 = 12 + (1×4) = 12 + 4 = 16 g/mol
Mole of CH4 =?
Mole = mass/Molar mass
Mole of CH4 = 8.80 / 16
Mole of CH4 = 0.55 mole.
Finally, we shall determine the volume of the gas at stp as illustrated below:
1 mole of a gas occupies 22.4 L at stp.
Therefore, 0.55 mole of CH4 will occupy = 0.55 × 22.4 = 12.32 L.
Thus, 8.80 g of CH4 occupies 12.32 L at STP.
Explanation:
There are two direct factors that affect solubility: temperature and pressure. Temperature affects the solubility of both solids and gases, but pressure only affects the solubility of gases.
H2O2(I)
C6H6(O)
CO2(I)
C2H6(O)
HNO3(I)
