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adoni [48]
3 years ago
14

Como purificar a agua

Chemistry
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

Usando un purificador que se hace con filtros

Explanation:

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Write the following isotope in nuclide notation (e.g., “ 14/6C”): copper-70
Mars2501 [29]

       ⁷⁰₂₉Cu

Explanation:

Copper-70 isotope in nuclide form.

  A nuclide is designated as:                    ₙᵇX

       Where X is the symbol of the atom

      b is the mass number of the atom

     n is the atomic number

Mass number is the number of protons and neutrons in an atom. These particles makes up the bulk of the mass of an atom.

Atomic number is the number of protons in an atom. For neutral atom, it is the same as the number of electrons.

    To write Copper-70 in nuclide format:

         Symbol of Copper is Cu

         Mass number is 70

       Atomic number from periodic table is 29

                             ⁷⁰₂₉Cu

Learn more:

Atomic number brainly.com/question/5425825

#learnwithBrainly

6 0
4 years ago
Choose any electromagnetic wave we have discussed and write ONE PARAGRAPH telling me about the uses/benefits of that electromagn
andrew11 [14]

Answer:

Visible Light

Explanation:

It helps us see things around us!

5 0
4 years ago
Read 2 more answers
Using the data in the chart, which of the following would be a correct analysis?
Temka [501]

Answer:  A.  Inverse relationship

Explanation:  A plot illustrates that as x increases, y decreases - an inverse relationship.

6 0
3 years ago
If glucose. galactose, and fructose all have the same formula, what is the difference about them
enot [183]
Glucose is blood sugar and is the main source for metabolism. Galactose is half of "milk sugar" (aka lactose). Fructose is "fruit sugar." it is true that all of these are 6- carbon sugars, but its how they are rearranged. "Shape determines function."
6 0
3 years ago
1.02 mg of a compound that is known to absorb at 340 nm is dissolved and diluted to 5.00 mL in a volumetric flask. A 1.00 mL ali
Vinvika [58]

Answer:

6.97 X 10^{-4} M

Explanation:

The concentration of the analyte in the 5-mL flask would be 6.97 X 10^{-4} M

This is a problem of simple dilution that can be solved using the dilution equation;

C1V1 = C2V2,

where C1 = initial concentration, V1 = initial volume, C2 = final concentration, and V2 = final volume.

<em>In this case, the initial concentration (C1) is not known, the initial volume (V1) is 1.00 mL, the final concentration is 6.97 x 10-5 M, and the final volume is 10.00 mL.</em>

Now, let us make the initial concentration the subject of the formula from the equation above;

C1 = C2V2/V1. Solve for C1 by substituting the other parameters.

C1 = 6.97 x 10-5 x 10/1 = 6.97 X 10^{-4} M

7 0
3 years ago
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