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KatRina [158]
3 years ago
13

Plz help me with these two problems I’m having such trouble

Mathematics
1 answer:
igomit [66]3 years ago
3 0
For No. 13 you need to calculate the distance each girl travels and compare to see whose distance is greater. The formula for distance is rate x time or d=rt. The rate is just how fast they consistently go.

Mia
d = r x t
d = 14 x 3/2
d = 21 miles

Chloe
d = r x t
d = 35 x 3/4 (btw 3/4 is just 45/60 simplified)
d = 105/4 = 26 1/4 miles

Final Answer: Chloe traveled further

For No. 14 we will recalculate Mia's distance but replace 1/5 hours with 2 hours because it says she will bike 30 minutes after Chloe had stopped. Afterwards we will compare Mia's new distance with Chloe's old distance.

Mia
d = r x t
d = 14 x 2
d = 28 miles

Final Answer: Yes Mia would be able to catch up to Chloe, and even surpass her in 30 minutes if Chloe stopped.

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Kazeer [188]

    Ok, use the sum of triangle theorm all angles of the triangle has a sum of 180 degrees. B is 90 degrees because it labeled it self ABC the A angle seems by the degree to be at the top of the triangle and there needs to be a 90 degree angle in a right triangle. Now if you add 90 + 28 you get 118 degrees subtract that from the sum of all the angles ( 180 degrees), and get 62 degrees as angle C.  Angle A is 28 degrees, angle B is 90 degrees, angle C is 62 degrees.  

5 0
3 years ago
JKLM is a rhombus. KM is 10 and JL is 24. Find the perimeter of the rhombus.
Ahat [919]
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units

5 0
3 years ago
The minimum size of a photo book ordered through a website is 6 pages. The website charges $1.70 per page for the first 6 pages.
m_a_m_a [10]
Well Okay, 1.70 x 6 + .90x, Your pretty much taking 1.70 multiply by 6 then adding .90 for every page after.
6 0
3 years ago
A recipe use 5 cups of flour for every 2 cups of sugar .a.how much sugar is used for 1 cup of flour? b.how much flour is used fo
zheka24 [161]

Answer:

1 cup of sugar per 2.5 cups of flour.

2.5 cups of flower per 1 cup of sugar.

17.5 cups of flower is used with 7 cups of sugar.

1.6 cups of sugar is used with 6 cups of flour.

Step-by-step explanation:

5 0
3 years ago
Drag the tiles to the boxes to form correct pairs.<br> Match the pairs of equivalent expressions.
Rashid [163]

Answer:

The following pairs/results are matched:

  • 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33
  • 3\left(3t-4\right)-\left(2t+10\right) = 7t-22
  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}
  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Step-by-step explanation:

Lets solve all the expressions to match the results.

  • 5\left(2t+1\right)+\left(-7t+28\right)

<em>Solving the expression</em>

5\left(2t+1\right)+\left(-7t+28\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

5\left(2t+1\right)-7t+28

10t+5-7t+28

3t+33

Therefore, 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33

  • 3\left(3t-4\right)-\left(2t+10\right)

<em>Solving the expression</em>

3\left(3t-4\right)-\left(2t+10\right)

9t-12-\left(2t+10\right)

9t-12-2t-10

7t-22

Therefore, 3\left(3t-4\right)-\left(2t+10\right) = 7t-22

  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)

<em>Solving the expression</em>

\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

4t-\frac{8}{5}-\left(3-\frac{4}{3}t\right)

4t-\frac{8}{5}-\left(-\frac{4t}{3}+3\right)

4t-\frac{8}{5}-3+\frac{4t}{3}

As

-3-\frac{8}{5}:\quad -\frac{23}{5}    and  \frac{4t}{3}+4t:\quad \frac{16t}{3}

So,

4t-\frac{8}{5}-3+\frac{4t}{3} will become \frac{16t}{3}-\frac{23}{5}

Therefore, \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}

  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)

<em>Solving the expression</em>

\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

-\frac{9}{2}t+3+\frac{7}{4}t+33

\mathrm{Group\:like\:terms}

\frac{9}{2}t+\frac{7}{4}t+3+33

\mathrm{Add\:similar\:elements:}\:-\frac{9}{2}t+\frac{7}{4}t=-\frac{11}{4}t

-\frac{11}{4}t+3+33

-\frac{11}{4}t+36

Therefore, \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Thus, the following pairs/results are matched:

  • 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33
  • 3\left(3t-4\right)-\left(2t+10\right) = 7t-22
  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}
  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Keywords: algebraic expression

Learn more about algebraic expression from brainly.com/question/11336599

#learnwithBrainly

5 0
3 years ago
Read 2 more answers
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