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pogonyaev
3 years ago
12

A ball is thrown vertically upward, which is the positive direction.A little later it returns to its point of release.The ball i

s in the air for a total time of 8.0 s.What is its initial velocity? Neglect air resistance
Physics
1 answer:
vivado [14]3 years ago
3 0

Answer:

u=78.4m/s

Explanation:

A ball is thrown vertically upward, which is the positive direction.A little later it returns to its point of release.The ball is in the air for a total time of 8.0 s.What is its initial velocity? Neglect air resistance

from newtons equation of motion

s=ut+\frac{1}{2}at^{2}

v=u+at

v=0 because at maximum height reached by the ball the ball stops moving

0=u-9.8*8

u=78.4m/s

u=initial velocity

v=final velocity

a=acceleration due to gravity, 9.81m/s^2

t=time it takes in air

s= distance to get to the maximum before returning

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Explanation:

If we are talking about an acceleration at a uniform rate, we are dealing with constant acceleration, hence we can use the following equation:

{V_{f}}^{2}={V_{o}}^{2}+2ad (1)

Where:

V_{f}=0 Is the final velocity of the plane (we know it is zero because we are told the pilot stops the plane at a specific distance)

V_{o} Is the initial velocity of the plane

a=-8m/s^{2} is the constant acceleration of the plane

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Isolating  V_{o} from (1):

V_{o}=\sqrt{-2ad} (2)

V_{o}=\sqrt{-2(-8m/s^{2})(484m)} (3)

Finally:

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