Answer:
Cr(s) ⟶ Cr⁴⁺(aq) + 4e⁻
Explanation:
1. Write the skeleton half-reaction
Cr(s) ⟶ Cr⁴⁺(aq)
2. Balance charge
Add electrons to the side that needs them.
You have 4+ on the right and 0 on the left. You must add 4e⁻ to the right to balance the charge.
Cr(s) ⟶ Cr⁴⁺(aq) + 4e⁻
Answer:
New temp = 135°C
Explanation:
From ideal gas equation
But; P1 = 10000Pa. P2 = 45000
V1 = 200 cc. V2 = 100 cc
T1 = 60°C. T2 = ??
From our formulae above
then T2= 45000×100×60÷ (10000×200)
T2= 135°C
The freezing point depression is a colligative property which means that it is proportional to the number of particles dissolved.
The number of particles dissolved depends on the dissociation constant of the solutes, when theyt are ionic substances.
If you have equal concentrations of two solutions on of which is of a ionic compound and the other not, then the ionic soluton will contain more particles (ions) and so its freezing point will decrease more (will be lower at end).
In this way you can compare the freezing points of solutions of KCl, Ch3OH, Ba(OH)2, and CH3COOH, which have the same concentration.
As I explained the solution that produces more ions will exhibit the greates depression of the freezing point, leading to the lowest freezing point.
In this case, Ba(OH)2 will produce 3 iones, while KCl will produce 2, CH3OH will not dissociate into ions, and CH3COOH will have a low dissociation constant.
Answer: Then, you can predict that Ba(OH)2 solution has the lowest freezing point.
Answer:
troposphere
he troposphere begins at the Earth's surface and extends up to the stratosphere. It contains roughly 80 percent of the mass of the entire atmosphere and is where most familiar weather patterns form.
Answer:
H2SO4
Explanation:
Firstly,
2.056% hydrogen = 2.056g of H
32.69% Sulphur = 32.69g of S
65.26% oxygen = 65.26g of O
Next, we convert each mass into moles by dividing by their respective molar mass:
H = 1, S = 32, O = 16
H = 2.056/1 = 2.056mol
S = 32.69/32 = 1.021mol
O = 65.26/16 = 4.078mol
Next, we divide each mole value by the smallest mole value (1.021)
H = 2.056/1.021 = 2.01
S = 1.021/1.021 = 1
O = 4.078/1.021 = 3.99
Approximately the ratio of H to S to O is 2:1:4, hence, the empirical formula for H, S and O is H2SO4.