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erastovalidia [21]
3 years ago
11

Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. solutes formula hydroio

dic acid hi calcium hydroxide ca(oh)2 hydrofluoric acid hf methyl amine ch3nh2 sodium bromide nabr propanol c3h7oh sucrose c12h22o11
Chemistry
2 answers:
Andreyy893 years ago
6 0
The correct classification of the solutes are as follows:

<span>hydroiodic acid hi                           =   strong electrolyte
calcium hydroxide ca(oh)2             =   weak electrolyte 
hydrofluoric acid hf                         =   weak electrolyte
methyl amine ch3nh2                     =   weak electrolyte
sodium bromide nabr                     =   strong electrolyte
propanol c3h7oh                            =   non electrolyte
sucrose c12h22o11                        =   non electrolyte

Strong electrolytes are substances that completely ionizes in aqueous solution while weak electrolytes are those that partially ionizes. Non electrolytes are substances that cannot conduct electric charge since there are no ions in the solution.</span>
zhenek [66]3 years ago
4 0

hydroodic acid h = strong electrolyte

calcium hydroxide ca (oh) 2 = weak electrolytes

hydrofluoric acid hf = weak electrolytes

methyl amine ch3nh2 = weak electrolytes

sodium bromide nabr = strong electrolyte

propanol c3h7oh = non electrolyte

c12h22o11 sucrose = not an electrolyte

<h2>Further Explanation </h2>

Electrolytes are solutions that can conduct electric current.

There are three types of solutions. The solution that can make the lamp turn bright is the strong electrolyte solution, the solution that can make the lamp turn dim is the weak electrolyte solution and the solution that does not turn on the lamp is the non-electrolyte solution.

Strong electrolyte solutions are perfectly ionized compounds when dissolved in water. Strong electrolyte solutions actually come from three types of solutions, namely water-soluble salts, strong acids, and strong bases. Strong electrolyte solutions derived from salt can be exemplified with a solution of NaCl salt. This solution can dissolve in water to produce cations and anions.

A weak electrolyte solution is a partially ionized solution in water. So this type of solution produces only a few ions in the water. Weak electrolytes usually come from two types of solutions, namely weak acids, and weak bases. One example of a weak acid which is also a weak electrolyte is Acetic Acid (HC2H3O2). Acetic acid has a different character from strong acids because if dissolved in water, acetic acid will not be fully ionized, only about 1% of the molecule will dissociate into ions in aqueous solution. Examples of weak acids: Acetic acid (HC2H3O2)

Learn more

electrolyte brainly.com/question/4284571

Details

Grade:  College

Subject:  Chemistry

keywords: electrolyte

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Explanation:

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5 0
2 years ago
What is the mass of HCL is consumed by the reaction of 1.5 mole of magnesium
photoshop1234 [79]

Answer: 109.5g

Explanation:

Mg + 2HCl —> MgCl2 + H2

From the equation,

1mole of Mg required 2moles of HCl

Therefore 1.5moles of Mg will require = 1.5 x 2 = 3 moles of HCl.

Molar Mass of HCl = 1+35.5 =36.5g/mol

Mass conc. Of HCl = 3 x 36.5 = 109.5g

3 0
3 years ago
What term describes a carbon atom that has four different groups bonded to it?
oee [108]
A carbon which is attached to four different atoms or group of atoms with different environment is called as Chiral Carbon or Asymmetric Carbon.

Non-<span>superimposable:
</span>                                     The mirror image (molecule) of chiral carbon cotaining compounds are Non.Superimposable on each other. They are called enantiomers of each other.

Polarized Light and Chiral Carbon:
                                                       When a polarized light is allowed to fall on either enantiomer of chiral compound, it is rotated other clockwise or anti-clockwise.

Examples:
                Below are three axamples of compounds containing chiral carbon.

8 0
3 years ago
A 3.42 gram sample of an unknown gas is found to occupy a volume of 1.90 L at a pressure of 547 mm Hg and a temperature of 33 °C
liq [111]
Use the Ideal Gas Law to find the moles of gas first.

Be sure to convert T from Celsius to Kelvin by adding 273.

Also I prefer to deal with pressure in atm rather than mmHg, so divide the pressure by 760 to get it in atm.

PV = nRT —> n = PV/RT
P = 547 mmHg = 547/760 atm = 0.720 atm
V = 1.90 L
T = 33°C = 33 + 273 K = 306 K
R = 0.08206 L atm / mol K

n = (0.720 atm)(1.90 L) / (0.08206 L atm / mol K)(306 K) = 0.0545 mol of gas

Now divide grams by mol to get the molecular weight.

3.42 g / 0.0545 mol = 62.8 g/mol
3 0
3 years ago
PLEASE HELP
neonofarm [45]

Answer:

The answer to your question is 0.10 M

Explanation:

Data

Molarity = ?

mass of Sucrose = 125 g

volume = 3.5 l

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of sucrose

C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)

               = 144 + 22 + 176

               = 342 g

2.- Convert the mass of sucrose to moles

                  342 g of sucrose ------------------- 1 mol

                  125 g of sucrose -------------------- x

                           x = (125 x 1) / 342

                           x = 0.365 moles

3.- Calculate the molarity

Molarity = 0.365 / 3.5

4.- Result

Molarity = 0.10

5 0
3 years ago
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