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ipn [44]
3 years ago
14

Burning something is always a chemical change that requires a fuel and

Chemistry
2 answers:
Misha Larkins [42]3 years ago
8 0
C . oxygen
i had this the other day
mrs_skeptik [129]3 years ago
7 0

Answer:

C

Explanation:

Oxygen is required in combustion because it's plays a reactive role in the process.

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True or false all countries are legally bound to survey and monitor for disease within their bodies
ra1l [238]

Answer:

False..........

7 0
3 years ago
Some patterns of electron configuration are listed below. In each case, [G] stands for a noble-gas core and n, m, or o stand for
Nonamiya [84]

Answer:

G]ns^2np^5 group 17 (p-block)

G]ns^2np^2 group 14 (p-block)

G]ns^2mf^14 group 16 (f-block)

Explanation:

The outermost electronic configuration of an element shows the group to which it belongs in the periodic table as shown above in the answer. In addition, to that, we can be able to know from its electronic configuration, whether the element is a metal or not.

For instance;

G]ns^2mf^14 is a rare earth metal, G]ns^2np^2 group 14 is a metalloid while G]ns^2np^5 group 17 is a nonmetal.

4 0
3 years ago
What is the relative humidity of the air when the dry-bulb temperature is 4°C and the dewpoint is -4°C?
boyakko [2]

Answer:56%

Explanation:

In the dewpoint chart when you line it up it ends up at 56%

3 0
3 years ago
Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr
Delvig [45]
<h2>Hello!</h2>

The answer is: Charle's Law.

<h2>Why?</h2>

The law that states that the volume and absolute temperature of a fixed quantity of gas (ideal gas) are proportional under constant pressure is the Charle's Law, also known as the law of volumes.

The law describes how a gas kept under constant pressure tends to expand when the temperature increases and it's described by the following equation:

\frac{V}{T}=k

Where,

V=Volume\\T=Temperature\\k=constant

Also, to describe the relationship between two differents volumes at different temperatures, we have:

\frac{V_{i}}{T_{i}}=\frac{V_{f}}{T_{f}}

Where,

V_{i}=InitialVolume\\T_{i}=InitialTemperature\\V_{f}=FinalVolume\\T_{f}=FinalTemperature

Have a nice day!

8 0
3 years ago
Read 2 more answers
What is the molecular formula of the hydrocarbon whose molar mass is 536 g/mol and contains 89.55 w/w% carbon?
leonid [27]

Given the percentage composition of HC as C → 81.82 % and H → 18.18 %

So the ratio of number if atoms of C and H in its molecule can will be:

C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8

So the Empirical Formula of hydrocarbon is:

C 3 H 8

As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol

Now let Molecular formula of the HC be ( C 3 H 8 ) n

Using molar mass of C and H the molar mass of the HC from its molecular formula is:

( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1

Hence the molecular formula of HC is C 3 H 8

Does that help?

7 0
3 years ago
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