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ipn [44]
3 years ago
14

Burning something is always a chemical change that requires a fuel and

Chemistry
2 answers:
Misha Larkins [42]3 years ago
8 0
C . oxygen
i had this the other day
mrs_skeptik [129]3 years ago
7 0

Answer:

C

Explanation:

Oxygen is required in combustion because it's plays a reactive role in the process.

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If you poor two ionic colloids into the same tube, what would the reaction most likely be?
o-na [289]

B implosion is the answer.

4 0
4 years ago
93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0 C.what would be the volume of this dry gas at STP
ExtremeBDS [4]
Let us assume that the oxygen behaves as an ideal gas such that we can use the ideal gas equation to solve for the number of moles of O2.
                       PV = nRT   ; n = PV/RT
Substituting the known values,
               n = (0.930 atm)(93/1000 L) / (0.0821 L.atm/mol.K)(10 + 273.15K)
                             n = 3.72 x 10^-3 mols
At STP, the volume of each mol of gas is equal to 22.4 L.
                          volume = (3.73 x 10^-3 mols) x (22.4 L/1 mol)
                           volume = 0.0833 L or 83.34 mL
5 0
4 years ago
What is the total energy change for the following reaction: H2 + I2 -> 2HI?
Paladinen [302]
I think the answer to this question will be +7kj/mol
4 0
4 years ago
A 25.0 mL sample of HCI reacted with 20.0 mL of 2.00 M NaOH. What is the molarity of the HCI?
Lemur [1.5K]

Answer:

Molarity of HCl = 1.6M

Explanation:

The chemical reaction equation is;

HCl(aq) + NaOH(aq) —> NaCl(aq) + H2O(l)

Now, molarity = number of moles/volume

Thus, for NaOH, we have;

Number of moles = molarity × volume = 2M × (20/1000) L

Number of moles = 0.04 moles

Using the coefficients in the chemical equation above, we can find the corresponding number of moles for HCl.

Number of moles of HCl = 0.04 moles NaOH × (1 mole of HCl/1 mole of HCl) = 0.04 moles of HCl

Thus;

Molarity of HCl = 0.04/(25/1000)

Molarity of HCl = 1.6M

5 0
3 years ago
Que. 1. Gallium has 2 naturally occuring Isotopes with mass numbers 69 & 71 respectively. What is the percentage abundance o
IgorC [24]

Isotopes are atoms of the same element that have different masses. The relative atomic mass (am) is a weighted average that takes into account the abundance of each isotope. We can calculate the relative atomic mass using the following expression.

am = \frac{\Sigma m_i  \times ab_i}{100}

where,

  • mi: mass of each isotope
  • abi: percent abundance of each isotope

For Gallium,

70.59 amu = \frac{69 amu\ x + 71 amu\ y}{100}     [1]

where "x" and "y" are the unknown abundances.

We also know that the sum of both abundances must be 100%.

x + y = 100

y = 100 - x   [2]

If we replace [2] in [1], we get

70.59 amu = \frac{69 amu\ x + 71 amu\ (100-x)}{100} \\7059 amu = -2 amu\ x + 7100amu \\x = 20.5

Then, in [2]

y = 100 - x = 100 - 20.5 = 79.5

In conclusion, Ga-69 has an abundance of 20.5% and Ga-71 has an abundance of 79.5%.

You can learn more about isotopes in: brainly.com/question/21536220?referrer=searchResults

7 0
3 years ago
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