What is the constant of variation for the quadratic variation

1 answer:

8 0

Let a be the constant the quadratic term
y = ax²
32 = a(2)²
a = 8
Using the same method for each pair of x and y, we can confirm that the value of a is 8.
The answer is A.

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CAN SOMEONE PLEASE ANSWER THIS SOON! THANK YOU!

lyudmila [28]

We want to find one-half of the reciprocal of 7/sqrt(98). Let's write down an expression for this:

$\dfrac{1}{2} \times \dfrac{\sqrt{98}}{7}$

We can rewrite 98 into $2 \times 49$

$\dfrac{1}{2} \times \dfrac{\sqrt{2 \times 49}}{7}$

$=\dfrac{1}{2} \times \dfrac{\sqrt{2} \times \sqrt{49}}{7}$

The square root of 49 is 7

$=\dfrac{1}{2} \times \dfrac{\sqrt{2} \times 7}{7}$

$=\dfrac{1}{2} \times\sqrt{2}$

$=\dfrac{\sqrt{2}}{2}$

This should be your answer. Let me know if you need any clarifications, thanks!

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sasho [114]

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Use the numbers 12 through 17. Place them in the connected circles so that the numbers along each line have a sum of 50. Do this

Furkat [3]

Answer:

[13, 15, 17, 16, 12]

[16, 12, 17, 13, 15]

[16, 15, 14, 13, 12]

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Step-by-step explanation:

Writing a Python code, I got the answers given, reading from left to right to down. For example, for [13, 15, 17, 16, 12], 13 is the top left circle, 15 is the middle right, 17 is the far right, 16 is the bottom left, and 12 is the bottom right

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Natali5045456 [20]

Answer:

cheating in entrance

Step-by-step explanation:

circumference: 14π

area: 49π

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