Question

A car accelerates uniformly from rest and covers a distance of 76 m in 6.3 s. If the diameter of a tire is 43 cm, find the angular acceleration of the wheel. Answer in units of rad/s 2 .

Answer 1

Answer:

17.81 rad/s²

Explanation:

Distance = 76 m = s

Time taken = 6.3 s

Diameter of tire = 43 cm = 0.43 m

Radius of wheel = 43/2 = 21.5 cm = 0.215 m

Acceleration

$s=ut+\frac{1}{2}at^2\\\Rightarrow 76=0+\frac{1}{2}a6.3^2\\\Rightarrow a=76\times 2\frac{1}{6.3^2}$

Angular acceleration

$\alpha=\frac{a}{R}\\\Rightarrow \alpha=\frac{76\times 2\frac{1}{6.3^2}}{0.215}\\\Rightarrow \alpha=17.81\ rad/s^2$

∴ Angular acceleration of the wheel is 17.81 rad/s²

Answer 2

Answer:

43 cm.

Explanation:

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