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gregori [183]
3 years ago
6

What statement best describes how wind weathered this rock

Physics
1 answer:
Kisachek [45]3 years ago
4 0

Answer:

the rock breaks down when the wind blows particles of sand against it.

Explanation:

because the sand can easily be decomposed and temperature easily accessible to it cause line of weaknesses of the rock to break down

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If the velocity of an object changes from 15 m/s during a time interval of 4s what is the acceleration of the object
Fiesta28 [93]
The acceleration of an object is defined as change in velocity divided by change in time, that is,
Acceleration = change in velocity / change in time
In the question given above, 
Change in velocity = 15
Change in time = 4
Acceleration = 15 /4 = 3.75
Therefore, acceleration = 3.8 m/s^2.
6 0
3 years ago
The thrust of a certain boat’s engine generates a power of 10kW as the boat moves at constant speed 10ms through the water of a
Lunna [17]

Answer:

The change in power is 4400 W.

Explanation:

Given that,

Power = 10 kW

Speed = 10 m/s

Increases speed = 12 m/s

Given equation is,

F=kv

We know that,

The power is,

P=Fv

Put the value of F into the formula

P=(kv)v

P=kv^2

P\propto v^2

We need to calculate the new power

Using formula for power

\dfrac{P}{P'}=\dfrac{v^2}{v'^2}

Put the value into the formula

\dfrac{10}{P'}=(\dfrac{10}{12})^2

P'=(\dfrac{12}{10})^2\times10

P'=14.4\ kW

We need to calculate the change in power

Using formula of change in power

\Delta P=P'-P

Put the value into the formula

\Delta P=14.4-10

\Delta P=4.4\ kW

\Delta P=4.4\times1000

\Delta P=4400\ W

Hence, The change in power is 4400 W.

6 0
4 years ago
Holding health care personal to lesser standards of care in emergencies is call the what statue?
olga55 [171]

Hello there,

Holding health care personal to lesser standards of care in emergencies is call the what statue?

Answer: A. Good Samaritan


3 0
3 years ago
A rifle bullet with a mass of 11.5 g traveling toward the right at 251 m/s strikes a large bag of sand and penetrates it to a de
BabaBlast [244]

To look for the acceleration, it will come from:

vf^2=v0^2+2ad 
where:
vf = final velocity = 0 
v0 = initial velocity =251 m/s 
a = acceleration 
d= distance traveled = 0.237 m 

0=251^2+2a(0.237 ) 
a= -251 ^2 / (2*0.237) =-132 913.502 m/s/s 

we find the force from: 

F = ma = 0.0115kg*(-1.32x10^5m/s/s) = -1518 N 

the negative sign shows that the force is in the direction contradictory the bullet's motion

5 0
3 years ago
A basketball center holds a basketball straight out, 2.0 m above the floor, and releases it. It bounces off the floor and rises
atroni [7]

Answer:

a) The velocity of the ball before it hits the floor is -6.3 m/s

b) The velocity of the ball after it hits the floor is 3.1 m/s

c) The magnitude of the average acceleration is 470 m/s². The direction is upward at an angle of 90º with the ground.

Explanation:

First, let´s calcualte how much time it takes the ball to hit the floor:

The equation for the position of the ball is:

y = y0 + v0 * t + 1/2 g * t²

Where:

y = position at time t

y0 = initial position

v0 = initial velocity

t = time

g = acceleration due to gravity

We take the ground as the origin of the reference system.

a) Since the ball is realesed and not thrown, the initial velocity v0 is 0. The direction of the acceleration is downward, towards the origin, then "g" will be negative. When the ball hits the ground its position will be 0. Then:

0 = 2.0 m + 0 m/s *t - 1/2 * 9.8 m/s²  * t²

-2.0 m = -4.9 m/s²  * t²

t² = -2.0 m / - 4.9 m/s²

t = 0.64 s

The equation for the velocity of a falling object is:

v = v0 + g * t      where "v" is the velocity

since v0= 0:

v = g * t = -9.8 m/s² * 0.64 s = -6.3 m/s

b) Now, we know that the velocity of the ball when it reaches the max height must be 0. We can obtain the time it takes the ball to reach that height from the equation for velocity and then use that time in the equation for position to obtain the initial velocity:

v = v0 + g * t

0 = v0 + g * t

-v0/g = t

now we replace t in the equation for position, since we know that the maximum height is 1.5 m:

y = y0 + v0 * t + 1/2* g * t²           y = 1.5 m       y0 = 0 m   t = -v0/g

1.5 m = v0 * (-v0/g) + 1/2 * g (-v0/g)²

1.5 m = - v0²/g - 1/2 * v0²/g

1.5 m = -3/2 v0²/g

1.5 m * (-2/3) * g = v0²

1.5 m * (-2/3) * (-9.8 m/s²) = v0²

v0 = 3.1 m/s

c) The average acceleration will be:

a = final velocity - initial velocity / time

a = 3.1 m/s - (-6.3 m/s) / 0.02 s = 470 m/s²

the direction of the acceleration is upward perpendicular to the ground.

The vector average acceleration will be:

a = (0, 470 m/s²) or (470 m/s² * cos 90º, 470 m/s² * sin 90º)

4 0
3 years ago
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