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svetoff [14.1K]
3 years ago
12

Whats the volume of a 2 year old

Chemistry
1 answer:
musickatia [10]3 years ago
5 0

Answer:

here's a great idea!

take a jug of water by finding the volume of that water and ask the 2 year old to chug it all in... the volume of water drank by the 2 year old is the volume of the two year old

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Does anyone know what convection,conduction,radiation??
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Answer:

Conduction is the transfer of thermal energy through direct contact. Convection is the transfer of thermal energy through the movement of a liquid or gas. Radiation is the transfer of thermal energy through thermal emission.

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3 years ago
Consider the five balanced chemical reactions listed below, all using O2 as a reactant. Normally, O2 is an excess reagent for re
ad-work [718]

Answer: option E. None because in all the reactions O2 is in excess

Explanation:

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What does fossil mean in my own words
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Answer: A thing that died a long time ago, and it's bones were preserved in the ground.

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Because yes

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There is a photon with a frequency of 8x10^12 Hz. What is the energy of this<br> photon?
jarptica [38.1K]

Answer:

33.085476 meV ≈ 33 meV

Explanation:

Hope this helped!

7 0
3 years ago
How much energy must be removed from a 94.4 g sample of benzene (molar mass= 78.11 g/mol) at 322.0 K to solidify the sample and
Kay [80]

Answer : The energy removed must be, 29.4 kJ

Explanation :

The process involved in this problem are :

(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)

The expression used will be:  

Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]

where,

Q = heat released for the reaction = ?

m = mass of benzene = 94.4 g

c_{p,s} = specific heat of solid benzene = 1.51J/g^oC=1.51J/g.K

c_{p,l} = specific heat of liquid benzene = 1.73J/g^oC=1.73J/g.K

\Delta H_{fusion} = enthalpy change for fusion = -9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g

Now put all the given values in the above expression, we get:

Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]

Q=-29427.312J=-29.4kJ

Negative sign indicates that the heat is removed from the system.

Therefore, the energy removed must be, 29.4 kJ

3 0
3 years ago
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