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rodikova [14]
3 years ago
14

What is the acceleration of a 1,500 kg car if the net force of 1,200 N is exerted on it?

Physics
1 answer:
liberstina [14]3 years ago
8 0

Answer:

a = 0.8 \frac{m}{{s}^{2} }

Explanation:

Newton's second Law:

F = ma

where

F: net force applied

m: mass of the object

a: acceleration

so you just need to substitute your values and solve for a. In other words...

1200 = 1500a \\ a =  \frac{1200}{1500}  = 0.8 \frac{m}{ {s}^{2} }

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Paha777 [63]

Answer:

v_o=2503.08\frac{m}{s}

Explanation:

Orbital velocity is the speed that a body that orbits around another body must have, for its orbit to be stable. For orbits with small eccentricity and when one of the masses is almost negligible compared to the other mass, like in this case, the orbital speed is given by:

v_o=\sqrt{\frac{GM}{r}}

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v_o=\sqrt{\frac{6.674*10^{-11}\frac{m^3}{kg\cdot s^2}(5.98*10^{24}kg)}{6.37*10^6m}}\\v_o=2503.08\frac{m}{s}

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3 years ago
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Answer:ture

Explanation:

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6 0
3 years ago
if you are in Birmingham AL, and you want to use your cell phone to talk to your cousin in Houston, TX, what must occur in order
lesantik [10]

Answer:

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Explanation:

From the example stated, what is required for such for a far distance, is a communication satellite link.

When a call is made by you, the a connection request is sent to the specified phone.The telephone tower receives the request from The mobile phone. The local tower(Birmingham,Al) is linked to a ground transmitter by the means of a Fiber optical cable.

A signal is sent to satellite via the ground transmitter.The satellite then set's off the local receiver in (Houston,Texas) which on it's end is connected to the local tower there. This tower then ask for your cousin's mobile for a call that will be incoming, a link is set, once he/she receives the call, from there a conversation can be done.

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4 years ago
What will be the acceleration of a 40-kilogram object that is pushed with a net force of 80 newtons?
ratelena [41]
= 80 N/40 kg
= 2 m/s 2
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3 years ago
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