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rodikova [14]
3 years ago
14

What is the acceleration of a 1,500 kg car if the net force of 1,200 N is exerted on it?

Physics
1 answer:
liberstina [14]3 years ago
8 0

Answer:

a = 0.8 \frac{m}{{s}^{2} }

Explanation:

Newton's second Law:

F = ma

where

F: net force applied

m: mass of the object

a: acceleration

so you just need to substitute your values and solve for a. In other words...

1200 = 1500a \\ a =  \frac{1200}{1500}  = 0.8 \frac{m}{ {s}^{2} }

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A toy airplane, flying in a horizontal, circular
Goshia [24]

Answer:

8.4 m/s

Explanation:

The toy completes 10 circle in 30 seconds. So its frequency of revolution is

f=\frac{10}{30 s}=0.33 Hz

The periof of revolution is the reciprocal of the frequency, so

T=\frac{1}{f}=\frac{1}{0.33 Hz}=3 s

The radius of the circular path is

r = 4.0 m

So the total distance covered by the toy in one circle is the length of the circumference:

2\pi r

And so the average speed is

v=\frac{2\pi r}{T}=\frac{2\pi (4.0 m)}{3 s}=8.4 m/s

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Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC.Express your answer in kilojoules
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The amount of heat will be equal to Lm.

Where L is the latent heat of fusion and m is mass of the ice.

Latent heat of ice = 80cal/g.

So the amount of heat required here will be 35× 80cal

= 2,800 cal.
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What is TeO3 compound name​
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A 2.0-kg projectile is fired with initial velocity components v0x = 30 m/s and v0y = 40 m/s from a point on the Earth's surface.
EleoNora [17]

(a) The kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.

(b) The work done  in firing the projectile is 2,500 J.

<h3>Kinetic energy of the projectile at maximum height</h3>

The kinetic energy of the projectile when it reaches the highest point in its trajectory is calculated as follows;

K.E = ¹/₂mv₀ₓ²

where;

  • m is mass of the projectile
  • v₀ₓ is the initial horizontal component of the velocity at maximum height

<u>Note:</u> At maximum height the final vertical velocity is zero and the final horizontal velocity is equal to the initial horizontal velocity.

K.E = (0.5)(2)(30²)

K.E = 900 J

<h3>Work done in firing the projectile</h3>

Based on the principle of conservation of energy, the work done in firing the projectile is equal to the initial kinetic energy of the projectile.

W = K.E(i) = ¹/₂mv²

where;

  • v is the resultant velocity

v = √(30² + 40²)

v = 50 m/s

W = (0.5)(2)(50²)

W = 2,500 J

Thus, the kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.

The work done  in firing the projectile is 2,500 J.

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

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Why do we use atomic models?
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Models help us to understand systems and their properties
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