A computer base unit of mass 7.5 kg is dragged along a smooth desk. If the normal contact force is 23N and the tension in the ar
m of the person dragging it acts at 23 degrees to the horizontal, then what is the total tension in the person's arms? ...?
2 answers:
Answer:
Total tension in the person's arm = 58.82 N
Explanation:
Normal Contact Force: Normal contact force is the vertical component of the contact force that is perpendicular to the surface that an object makes contact with.
As shown in fig.1 in the diagram on the attached file below.
The Normal contact force (R) = Tsinθ = The vertical component of T
Where T = Total tension in the person's arm (N), θ = angle of inclination to the horizontal.
∴ R = Tsinθ
T = R/sinθ where R= 23N, θ =23°
T = 23/sin23° = 23/0.391
T = 58.82 N
∴ Total tension in the person's arm = 58.52 N
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Answer:
10s
Explanation:
Acceleration is a measure of a rate of change of velocity, or in other words, a measure of how quickly the velocity is changing.
If acceleration is constant, then the velocity is changing by a constant amount.
With an acceleration of 100 m/s^2, starting from the launching pad (and thus, an initial velocity of zero), we can calculate how long it will take to reach a final velocity of 1000m/s with the following formula:
where "v" is the final velocity at some later time "t", "a" is the constant acceleration, and "v" sub-zero is the initial velocity.
So, it will take 10 seconds for the rocket to reach 1000m/s when starting from the launching pad, with a constant velocity of 100m/s^2.
<u>Verification:</u>
In this situation, it is quick to verify that 10 seconds is correct by looking at what the velocities will be each second.
Recognizing that the acceleration is , the velocity increases by 100 units [m/s] every second.
At time 0[s], the velocity is 0[m/s]
At time 1[s], the velocity is 100[m/s]
At time 2[s], the velocity is 200[m/s]
At time 3[s], the velocity is 300[m/s]
At time 4[s], the velocity is 400[m/s]
At time 5[s], the velocity is 500[m/s]
At time 6[s], the velocity is 600[m/s]
At time 7[s], the velocity is 700[m/s]
At time 8[s], the velocity is 800[m/s]
At time 9[s], the velocity is 900[m/s]
At time 10[s], the velocity is 1000[m/s]
So, indeed, after 10 seconds, the velocity reaches 1000 m/s