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guapka [62]
3 years ago
6

A point charge q1 = -2.3 μC is located at the origin of a co-ordinate system. Another point charge q2 = 6.2 μC is located along

the x-axis at a distance x2 = 9.9 cm from q1.
Physics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

-13.09 N

Explanation:

Hello!

With Coulomb's law, the force of attraction between two charges can be calculated:

F=(K*q_1*q_2)/r^2

K=9*〖10〗^9  (N*m^2)/C^2

9,9 cm = 0,099 m

-2,3µC= -2,3*〖10〗^-6 C

6,2µC= 6,2*〖10〗^-6 C

By simplifying units the force remains in Newton.

Successes with your homework!

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Zigmanuir [339]

(a) The object moves with uniform velocity from A to B.

(b) The object moves with constant velocity from B to C.

(c) The object moves with increasing velocity from C to D.

<h3>Velocity of the object from point A to B</h3>

V(A to B) = (6 - 0)/(4 - 0) = 1.5 m/s

<h3>Velocity of the object from point B to C</h3>

V(B to C) = (6 - 6)/(11 - 4) = 0 m/s

<h3>Velocity of the object from point C to D</h3>

V(C to D) = (7 - 6)/(12 - 11) = 1 m/s

final velocity = 1 + 1.5 m/s = 2.5 m/s

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The object moves with uniform velocity from A to B.

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Learn more about velocity here: brainly.com/question/6504879

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