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3 years ago

If a car accelerates at a constant rate of 3m/s^2, what is the velocity of the car after 4 seconds

Physics

2 answers:

vaieri [72.5K]3 years ago

6 0

It'll be 12 m/s greater than it was when the acceleration began.

Ne4ueva [31]3 years ago

3 0

V=d/t

V=3/4

V=0.75

Hope this helps and is correct :)

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A car starts from rest and acquires a velocity of 50m/s in 3secs. Calculate i) acceleration ii) distance covered.

mafiozo [28]

Answer: 75.02 m

Explanation:

u = 0 ( starts from rest )

v = 50 m/s

t = 3 s

( i ) a = v - u / t

= 50 - 0 /3

= 16.67

( ii ) s = ut + 1/2 at²

= 0 × 3 + 1/2 × 16.67 × 3 × 3

= <u>75.02 m</u>

Hope this helps...

4 0

2 years ago

12.5 Round to the nearest hundredth.

7nadin3 [17]

I think its 13...........

7 0

2 years ago

A sound wave has a speed of 343 m/s in air. What is the wavelength of a sound wave with a frequency of 686 Hz

Svetradugi [14.3K]

Wavelength is the distance between 2 adjacent points in a wave

we can use the following equation to find the wavelength of a sound wave

wavelength = speed / frequency

frequency is the number of waves passing a point in 1 second

substituting the values in the equation

wavelength = 343 m/s / 686 Hz

wavelength = 0.5 m

wavelength of the wave is 0.5 m

6 0

2 years ago

Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 168 cm , but its circumference is decreasi

DedPeter [7]

Answer:

103.1 V

Explanation:

We are given that

Initial circumference=C=168 cm

$\frac{dC}{dt}=-15cm/s$

Magnetic field,B=0.9 T

We have to find the magnitude of the emf induced in the loop after exactly time 8 s has passed since the circumference of the loop started to decrease.

Magnetic flux= $\phi=BA=B(\pi r^2)$

Circumference,C= $2\pi r$

$r=\frac{C}{2\pi}$

$r=\frac{168}{2\pi}$ cm

$\frac{dr}{dt}=\frac{1}{2\pi}\frac{dC}{dt}=\frac{1}{2\pi}(-15)=-\frac{15}{2\pi} cm/s$

$\int dr=-\int \frac{15}{2\pi}dt$

$r=-\frac{15}{2\pi}t+C$

When t=0

$r=\frac{168}{2\pi}$

$\frac{168}{2\pi}=C$

$r=-\frac{15}{2\pi}t+\frac{168}{2\pi}$

E= $-\frac{d\phi}{dt}=-\frac{d(B\pi r^2)}{dt}=-2\pi rB\frac{dr}{dt}$

$E=-2\pi(-\frac{5}{2\pi}t+\frac{168}{2\pi})B\times -\frac{15}{2\pi}$

t=8 s

B=0.9

$E=2\pi\times \frac{15}{2\pi}\times 0.9(-\frac{15}{2\pi}(8)+\frac{168}{2\pi})$

$E=103.1 V$

6 0

3 years ago

Paragraph about how the constellations were used by ancient civilizations.

nata0808 [166]

Answer:

What does this mean ?

Explanation:

8 0

3 years ago