TLDR: R=30 Ohms, I=2 Amps, 12V, 28V, 20V, respectively.
Alright, let’s break this down. There are three resistors in this circuit, meaning that we have to find the equivalent resistance. Luckily, they are all in parallel with one another; this means we can add the resistances together without having to do inverses like in a series problem. This means that the equivalent resistance, Req, would equal:
Req=R1 + R2 + R3
Req=6 + 14+ 10
Req=30 Ohms
This means that we could theoretically replace all three resistors with a 30 Ohm resistor and accomplish the same goal. Now, the entire voltage of the system would normally be reduced to zero after passing through the resistors - in this case, the 60 Vs would be lost after passing through 30 Ohms. This means we’re losing 2V/Ohm; now we can figure out how much we’re losing at each resistor.
By losing 2V per Ohm, we’re losing 12 V at the first resistor, 28 V at the second resistor, and 20 V at the third resistor.
Finally, we can calculate the current through the circuit; for a series circuit, the current remains the same. Using V=IR, we can find that:
V=IR
60 V = I(30 Ohms)
I = 2 Amps
The current passing through the circuit is 2 Amps.
Hope this helps!
So we know coefficient of f times normal force is friction. So do 100= .25 times x. Now solve for x. You get 400. So 400 is the normal force. And we know normal force equals weight in these types of problems so the answer is 400
Answer:
No, they will not change.
Explanation: