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omeli [17]
4 years ago
10

Required Information

Physics
1 answer:
solmaris [256]4 years ago
3 0

Answer:

\Delta V=-18,62784\ mm^3

Explanation:

The question can be answered by using the thermal expansion theory. We need to use the formulas for the volume expansion.

Let's assume we have some material with a linear thermal expansion coefficient \alpha, an initial volume V_o to an initial temperature T_o which is later to a final temperature T_f

The change in volume due to thermal expansion is

\Delta V=3\alpha V_o (T_f-T_o)

The teeth filling has an initial volume of

V_o=320\ mm^3

At a temperature of

T_o=37\ ^oC

Its linear thermal expansion coefficient is

\alpha=420x10^{-6}\ ^oK^{-1}

The final temperature of the ice cream which caused the filling to come out was

T_f=-9.2\ ^oC

Since the thermal coefficient is expressed in reciprocal Kelvin degrees, we need to convert the temperatures to ^oK

T_o=37^oC-273.15=-236.15^oK

T_f=-9.2^oC-273.15=-282.35^oK

Thus we have

\Delta V=3(420x10^{-6}\ ^oK^{-1}) (320\ mm^3) (-282.35^oK+236.15^oK)

\Delta V=0,4032\ mm^3(-46.2^oK)

\Delta V=-18,62784\ mm^3

This differential contraction of the filling relative to the rest of the tooth caused the event

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Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another
Tanya [424]

Answer:I_2=0.618\times 10^{-7} W/m^2

Explanation:

Given

Distance between source and  receiver d_1=3 m

Sound Intensity I_1=1.1\times 10^{-7} W/m^2

Distance of of second observer d_2=4 m

Intensity varies as

I\propto \frac{1}{d^2}

using this

I=\frac{k}{d^2}

\frac{I_1}{I_2}=\frac{d_2^2}{d_1^2}

\frac{1.1\times 10^{-7}}{I_2}=\frac{4^2}{3^2}

I_2=0.75^2\times 1.1\times 10^{-7}

I_2=0.618\times 10^{-7} W/m^2

     

6 0
3 years ago
Suppose a 1 Gbps point-to-point link is being set up between the Earth and a new lunar colony. The distance from the moon to Ear
vagabundo [1.1K]

Answer:

The time required to send the data from Earth to Moon will be 1.28s while for a two way communication, to send it back to the earth, it will take double time i.e. <em>RTT = 2.56s </em>

Explanation:

Distance between Earth and Moon = 385,000 km = 3.85 x 10⁸m

Speed of data travel = speed of light ≈ 3 x 10⁸m/s

As, v=d/t

t=d/v

t=\frac{3.85*10^{8} }{3*10^{8}}

t=1.28s

RTT = Double of single way time taken = 2x1.28

<em><u>RTT=2.56s</u></em>

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When water (H₂O) freezes into ice, some of the properties have changed. What stays the same?
erastova [34]

Answer:

1st one

identity of the H₂O

When water (H2O) freezes into ice, some of the properties have changed but the identity of the H2O is the same. Explanation; Water can exist in liquid, solid; ice and gaseous state; steam. Freezing occurs when water is continuously cool until it turns to solid ice, water freezes at zero degree Celsius

Hope This Helps

4 0
2 years ago
You throw a ball with a mass of 0.50 kg against a brick wall. It hits the wall moving horizontally to the left at 20 m/s and reb
Orlov [11]

Answer:

The value of impulse of the net force on the ball during its collision with wall is  I = 15\ kg \frac{m}{s}

The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N

Explanation:

Mass of the ball = 0.5 kg

Horizontal velocity V_{x} = 20 \frac{m}{s}

Velocity after collision V_{-x} = - 10 \frac{m}{s}

(A). Impulse of the net force on the ball during its collision with wall is

I =  m (V_{x} - V_{-x})

I = 0.5 × (20 + 10)

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This is the value of impulse of the net force on the ball during its collision with wall.

(B). The magnitude of average horizontal force

F = \frac{I}{T}

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F = \frac{15}{0.001}

F = 15000 N

This is the value of average horizontal force that the wall exerts on the ball during the impact.

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Rahul and Sonia were playing with blocks and each of them made a train out of them. Both of them thought of measuring the length
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