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Ahat [919]
3 years ago
10

How do the most common forms of energy work?

Physics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

activity 2

Explanation:

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What are the units of atmospheric pressure?
erastova [34]

Answer:

a unit of pressure defined as 101325 Pa

Explanation:

6 0
4 years ago
Suppose you have a pendulum clock which keeps correct time on Earth(acceleration due to gravity = 1.6 m/s2). For ever hour inter
kaheart [24]

The moon clock is A) (9.8/1.6)h compared to 1 hour on Earth

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

In this problem, we want to compare the period of the pendulum on Earth with its period on the Moon. The period of the pendulum on Earth is

T_e=2\pi \sqrt{\frac{L}{g_e}}

where

g_e = 9.8 m/s^2 is the acceleration of gravity on Earth

The period of the pendulum on the Moon is

T_m=2\pi \sqrt{\frac{L}{g_m}}

where

g_m = 1.6 m/s^2 is the acceleration of gravity on the Moon

Calculating the ratio of the period on the Moon to the period on the Earth, we find

\frac{T_m}{T_e}=\frac{g_e}{g_m}=\frac{9.8}{1.6}

Therefore, for every hour interval on Earth, the Moon clock will display a time of

A) (9.8/1.6)h

#LearnwithBrainly

6 0
3 years ago
A positive rod is placed to the left of sphere A ,and the spheres are separated
Romashka [77]
When a positive rod is placed to the right of sphere B, and the spheres are separated, the reason behind this is the same charge on the sphere as the rod i.e. the right of the sphere also had a positive charge. Thus, the same positive charges could not reside on the right side surface of the sphere due to which it separation happens.

Read more on Brainly.com - brainly.com/question/4135790#readmore
5 0
3 years ago
Read 2 more answers
A fighter plane flying at constant speed 420 m/s and constant altitude 3300 m makes a turn of curvature radius 11000 m. On the g
Arada [10]

Answer:

"Apparent weight during the "plan's turn" is  519.4 N

Explanation:

The "plane’s altitude" is not so important, but the fact that it is constant tells us that the plane moves in a "horizontal plane" and its "normal acceleration" is \mathrm{a}_{\mathrm{n}}=\frac{v^{2}}{R}

Given that,

v = 420 m/s

R = 11000 m

Substitute the values in the above equation,

a_{n}=\frac{420^{2}}{11000}

a_{n}=\frac{176400}{11000}

a_{n}=16.03 \mathrm{m} / \mathrm{s}^{2}

It has a horizontal direction. Furthermore, constant speed implies zero tangential acceleration, hence vector a = vector a N. The "apparent weight" of the pilot adds his "true weight" "m" "vector" "g" and the "inertial force""-m" vector a due to plane’s acceleration, vectorW_{\mathrm{app}}=m(\text { vector } g \text { -vector a })

In magnitude,

| \text { vector } g-\text { vector } a |=\sqrt{\left(g^{2}+a^{2}\right)}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=\sqrt{\left(9.8^{2}+16.03^{2}\right)}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=\sqrt{(96.04+256.96)}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=\sqrt{353}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=18.78 \mathrm{m} / \mathrm{s}^{2}

Because vector “a” is horizontal while vector g is vertical. Consequently, the pilot’s apparent weight is vector

\mathrm{W}_{\mathrm{app}}=(18.78 \mathrm{m} / \mathrm{s}^ 2)(53 \mathrm{kg})=995.77 \mathrm{N}

Which is quite heavier than his/her true weigh of 519.4 N

7 0
4 years ago
Read 2 more answers
A singly charged 7Li ion has a mass of 1.16 10-26 kg. It is accelerated through a potential difference of 523 V and subsequently
mel-nik [20]

Answer:

R=0.023m

Explanation:

From the question we are told that:

Mass m=1.16*10^{-26}

Potential difference V=523V

Magnitude m=0.370 T

Generally the equation for Velocity is mathematically given by

\frac{1}{2}mv^2=ev

v=\frac{2ev}{m}

v=\frac{2*1.6*10^{-19}*542}{1.16*10^{-26}}

v=12.22*10^4m/s

Generally the equation for Force is mathematically given by

F=qvBsin \theta

Where

qVB=m\frac{v^2}{R}

F=m\frac{v^2}{R}sin\theta

Therefore

R=\frac{mv}{qB sin \theta}

R=\frac{1.6*10^{-26}*12.2*10^{4}}{1.60*10^{-19}*0.394 sin 90}

R=0.023m

8 0
3 years ago
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