Answer:
the relative density of the gravel in the field is 0.7365 or 73.65%
Explanation:
Given that;
wet density of gravel 
= 2.3 Mg/m³
field water content w = 16%
density of solids in lab 
= 2.70 Mg/m³
Maximum void ratio 
= 0.59
Minimum void ratio 
= 0.28
first we determine the dry density of gravel 
= / 1+ w
= 2.3 Mg/m³ / 1 + 0.16 = 2.3/1.16 = 1.9827 Mg/m³
we know that; 
= 1000 kg/m³ = 1 g/cm³
Specific Gravity of soil G = / = 2.70 Mg/m³ / 1 = 2.70 Mg/m³
eo = ((G×)/) - 1
eo = (( 2.70 × 1) / 1.9827 ) - 1
eo = 1.3617 - 1
Co = 0.3617
so Relative density 
will be;
= - eo / -
we substitute
= 0.59 - 0.3617 / 0.59 - 0.28
= 0.2283 / 0.31
= 0.7365 or 73.65%
Therefore; the relative density of the gravel in the field is 0.7365 or 73.65%
Mass x SH x °C (or K) ΔT
= 75g x 0.45J/g/K x 6.0 ΔT
= 202.5 Joules of heat absorbed.
(202.5J / 4.184J/cal = 48.4 calories).
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Answer:
Waves can be measured using wavelength and frequency. ... The distance from one crest to the next is called a wavelength (λ). The number of complete wavelengths in a given unit of time is called frequency (f). As a wavelength increases in size, its frequency and energy (E) decrease.
